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3 years ago

A football player has a mass of 65 kg and is moving with a velocity of 5 m/s. What is the players momentum

2 answers:

6 0

Steps: 1)Data: Mass of the football player=m=65kg Velocity of football player=v=5m/s 2)Formula: P=mv Or Momentum=(mass of the object)(velocity of the object) 3)Calculation: P=(65)(5)=325 kgm/s Hope it helped!

GenaCL600 [577]3 years ago

4 0

The answer is : 325 kg . m/s

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The attractive electrostatic force between the point charges +8.44 ✕ 10-6 and q has a magnitude of 0.961 n when the separation b

d1i1m1o1n [39]

The electrostatic force between two charges Q1 and q is given by
$F=k_e \frac{Q_1 q}{r^2}$
where
ke is the Coulomb's constant
Q1 is the first charge
q is the second charge
r is the distance between the two charges

Re-arranging the formula, we have
$q= \frac{F r^2}{k_e Q_1}$
and since we know the value of the force F, of the charge Q1 and the distance r between the two charges, we can calculate the value of q:
$q= \frac{(0.961 N)(0.67 m)^2}{(8.99 \cdot 10^9 N m^2 C^{-2})(+8.44\cdot 10^{-6}C)}=5.69 \cdot 10^{-6} C$

And since the force is attractive, the two charges must have opposite sign, so the charge q must have negative sign.

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3 years ago

A point from which the position of other objects can be described is called what?

Alisiya [41]

Answer:

Reference Point

Explanation:

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3 years ago

A billion years ago, Earth and its moon were just 200000 kilometers apart. Express this distance in meters.

Luda [366]

Answer:

The value is $x = 200000000 \ m$

Explanation:

From the question we are told that

The distance between the earth and the moon is $d = 200000 \ km$

Generally ,

$1 \ km = 1000 \ m$

$200000 \ km \to x \ m$

=> $x = \frac{200000 * 1000}{1 }$

=> $x = 200000000 \ m$

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3 years ago

Which experiment proved light was a wave?

pshichka [43]

Answer:

The answer is B) Double slit

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3 years ago

Dr. Kirwan is preparing a slide show that he will present to the executive board at tonight's committee meeting. He places a 3.5

lisov135 [29]

Answer:

A) d_o = 20.7 cm

B) h_i = 1.014 m

Explanation:

A) To solve this, we will use the lens equation formula;

1/f = 1/d_o + 1/d_i

Where;

f is focal Length = 20 cm = 0.2

d_o is object distance

d_i is image distance = 6m

1/0.2 = 1/d_o + 1/6

1/d_o = 1/0.2 - 1/6

1/d_o = 4.8333

d_o = 1/4.8333

d_o = 0.207 m

d_o = 20.7 cm

B) to solve this, we will use the magnification equation;

M = h_i/h_o = d_i/d_o

Where;

h_o = 3.5 cm = 0.035 m

d_i = 6 m

d_o = 20.7 cm = 0.207 m

Thus;

h_i = (6/0.207) × 0.035

h_i = 1.014 m

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3 years ago