Answer:
Let me look up a couple of things regarding this question.
Explanation:
Then I will get back to you.
Answer:
1.44 m/s²
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration

This velocity will be the initial velocity of the car when it passes through the first building

The acceleration of the car is 1.44 m/s²
Answer:
Option B. 8.1
Explanation:
From the question given above, the following data were obtained:
Angle θ = 71°
Hypothenus = 25
Adjacent = x
Thus, we can obtain the x component of the vector by using the cosine ratio as illustrated below:
Cos θ = Adjacent /Hypothenus
Cos 71 = x/25
Cross multiply
x = 25 × Cos 71
x = 25 × 0.3256
x = 8.1
Therefore, the x component of the vector is 8.1
Answer:
h = 4271.43 m
Explanation:
given,
Volume of the water = 1 m³
temperature decrease by = 10°C
heat removed from water
Q = m c ΔT
Q = ρ V c ΔT
= 1000 × 1 × 4186 × 10
= 4.186 × 10⁷ J
energy is used to do work to move the water against its weight
Q = force × displacement
4.186 × 10⁷ J = m g × h
4.186 × 10⁷ J = 1000 × 1 × 9.8 × h
h = 4271.43 m
hence, the change in height of is equal to h = 4271.43 m
Answer:
Explanation:
one end of tank will be circular in shape . Area of circle A
= π r² , r is radius of the circle
= 3.14 x 3²
A = 28.26 ft³
To calculate force on the circular area , we first find pressure at the center of the circle which is at depth equal to r
pressure at the center = h d g ' here h = depth = r , d = density of milk
pressure = 3 x 64.6 x 32 poundal / ft²
= 6201.6 poundal / ft²
total force on circular face = pressure at the center x area of circle
= 6201.6 x 28.26
= 175257.21 poundal .