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Tanya [424]
3 years ago
13

A football player has a mass of 65 kg and is moving with a velocity of 5 m/s. What is the players momentum

Physics
2 answers:
Archy [21]3 years ago
6 0
Steps: 1)Data: Mass of the football player=m=65kg Velocity of football player=v=5m/s 2)Formula: P=mv Or Momentum=(mass of the object)(velocity of the object) 3)Calculation: P=(65)(5)=325 kgm/s Hope it helped!
GenaCL600 [577]3 years ago
4 0

The answer is : 325 kg . m/s

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The main product of the photosynthesis reaction is A. sugar. B. fat. C. protein. D. DNA.
Firlakuza [10]
The answer is A. Sugar
3 0
3 years ago
Read 2 more answers
The water hose at your home outputs 24 gallons of water a minute. how many cubic centimeters per second does the hose output? th
adoni [48]

When we convert 24 gallon/min to cubic centimeters per second (cm³/s), the result obtained is 1514.164 cm³/s

<h3>How to convert 24 gallon/min to cm³/min</h3>

We'll begin by converting 24 gallon/min to cm³/min. This can be obtained as follow:

1 gallon/min = 3785.41 cm³/min

Therefore,

24 gallon/min = (24 gallon/min × 3785.41 cm³/min) / 1 gallon/min

24 gallon/min = 90849.84 cm³/min

<h3>How to convert 90849.84 cm³/min to cm³/s</h3>

We can convert 90849.84 cm³/min to cm³/s as follow:

60 cm³/min = 1 cm³/s

Therefore,

90849.84 cm³/min = (90849.84 cm³/min × 1 cm³/s) / 60 cm³/min

90849.84 cm³/min = 1514.164 cm³/s

Thus,

24 gallon/min = 1514.164 cm³/s

Learn more about conversion:

brainly.com/question/2139943

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7 0
1 year ago
Does 3.60 x 10 ⁻² have 2 significant figures
Mandarinka [93]

Answer:

Number of Significant Figures: 2

The Significant Figures are 3 6

Explanation:

= 3.60 × 102

(scientific notation)

= 3.60e2

(scientific e notation)

= 360 × 100

(engineering notation)

(one)

= 360

(real number)

4 0
2 years ago
A wagon wheel consists of 8 spokes of uniform diamter, each of mass m, and length L. The outer ring has a mass m rin. What is th
Genrish500 [490]

Answer:

L^2(\dfrac{8m}{3}+m_r)

Explanation:

m = Mass of each rod

L = Length of rod = Radius of ring

m_r = Mass of ring

Moment of inertia of a spoke

\dfrac{mL^2}{3}

For 8 spokes

8\dfrac{mL^2}{3}

Moment of inertia of ring

m_rL^2

Total moment of inertia

8\dfrac{mL^2}{3}+m_rL^2\\\Rightarrow L^2(\dfrac{8m}{3}+m_r)

The moment of inertia of the wheel through an axis through the center and perpendicular to the plane of the ring is L^2(\dfrac{8m}{3}+m_r).

3 0
3 years ago
an aircraft landing on an air craft carrier is brought to a complete stop from an inital velocity of 215km/hr in 2.7 seconds. wh
worty [1.4K]

u= 215 km/hr = 215 * 1000/ 3600 = aprx 60m/s
v=0
t=2.7sec
v= u - at
u= at
60/2.7 = 22.23 m/s^2



Hope it helps
8 0
2 years ago
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