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3 years ago

Give 3 examples of conduction, radiation, and convection.

Chemistry

2 answers:

Feliz [49]3 years ago

7 0

Answer:

Radiation: Radio Waves, Conduction: An ice cube on a warm hand, Convection: A radiator

cupoosta [38]3 years ago

3 0

Answer:Conduction: Touching a stove and being burned. Ice cooling down your hand

Convection: Hot air rising, cooling, and falling (convection currents)

Radiation: Heat from the sun warming your face

Explanation:

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What is the mole fraction of O2O2 in a mixture of 15.1 gg of O2O2, 8.19 gg of N2N2, and 2.46 gg of H2H2

SVETLANKA909090 [29]

Answer:

Mole fraction O₂= 0.43

Explanation:

Mole fraction is the moles of gas/ total moles.

Let's determine the moles of each:

Moles O₂ → 15.1 g / 16 g/mol = 0.94

Moles N₂ → 8.19 g / 14 g/mol = 0.013

Moles H₂ → 2.46 / 2 g/mol = 1.23

Total moles = 2.183

Mole fraction O₂= 0.94 / 2.183 → 0.43

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4 years ago

What information does the third quantum number of an electron give? A. The direction the electron in spinning B. The energy leve

Juli2301 [7.4K]

The information that the third quantum number of an electron gives is the direction the electron in spinning. That is option A.

<h3>What are quantum numbers?</h3>

Quantum number are those numbers that are used to specify the properties of the atomic orbitals and the electrons in those orbitals.

The types of quantum numbers include the following:

principal,

azimuthal,

magnetic, and spin.

The third quantum number is shows the direction of the electron while spinning through specifying its angular momentum.

Learn more about orbitals here:

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2 years ago

John was considered to be a pillar in the early church?

o-na [289]

Yes he was a pillar in the early church

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4 years ago

Read 2 more answers

A stock solution of ammonia in water is 28 wt% NH3. The Formal Weight (FW) of NH3 is 17.03 g/mol). The solution density at room

weqwewe [10]

Answer:

[NH₃] = 14.7 mol/L

Explanation:

28 wt% is a type of concentration that indicates that 28 g of ammonia is contained in 100 g of solution.

Let's determine the amount of ammonia:

28 g . 1 mol / 17.03g = 1.64 moles of NH₃

You need to consider that, when you have density's data it is always referred to solution:

Mass of solution is 100 g, let's find out the volume

0.90 g/mL = 100 g /V

V = 100 g / 0.90mL/g → 111.1 mL

We convert the volume to L → 111.1 mL . 1 L/1000mL = 0.1111 L

mol/L = 1.64 mol/0.1111L → 14.7 M

mol/L = M → molarity a sort of concentration that indicates the moles of solute in 1L of solution

4 0

3 years ago

The balanced redox reactions for the sequential reduction of vanadium are given below.

Minchanka [31]

Answer : 0.0392 grams of Zn metal would be required to completely reduced the vanadium.

Explanation :

Let us rewrite the given equations again.

$2VO_{2}^{+} (aq)+ 4H^{+}(aq) + Zn (s)\rightarrow 2VO^{2+}(aq)+Zn^{2+}+2H2O(l)$ $2VO^{2+}(aq)+ 4H^{+}(aq) + Zn (s)\rightarrow 2V^{3+} (aq)+Zn^{2+}+2H2O(l)$

$2V^{3+} (aq)+ Zn (s)\rightarrow 2V^{2+}(aq)+Zn^{2+}(aq)$

On adding above equations, we get the following combined equation.

$2VO_{2}^{+} (aq)+ 8H^{+} (aq) + 3Zn (s)\rightarrow 2V^{2+}(aq)+3Zn^{2+}(aq)+4H_{2}O(l)$

We have 12.1 mL of 0.033 M solution of VO₂⁺.

Let us find the moles of VO₂⁺ from this information.

$12.1 mL \times \frac{1L}{1000mL}\times \frac{0.033mol}{L}=0.0003993mol NO_{2}^{+}$

From the combined equation, we can see that the mole ratio of VO₂⁺ to Zn is 2:3.

Let us use this as a conversion factor to find the moles of Zn.

$0.0003993mol NO_{2}^{+}\times \frac{3mol Zn}{2molNO_{2}^{+}}=0.00059895mol Zn$

Let us convert the moles of Zn to grams of Zn using molar mass of Zn.

Molar mass of Zn is 65.38 g/mol.

$0.00059895mol Zn\times \frac{65.38gZn}{1molZn}=0.0392gZn$

We need 0.0392 grams of Zn metal to completely reduce vanadium.

6 0

3 years ago