Question

For an office job I need to pick 3 candidates put of a pool of 5. How many choices do I have?

Answer 1

$C_5^3= \frac{5!}{3!(5-3)!}= \frac{1*2*3*4*5}{1*2*3*2!}= \\\\ =\frac{4*5}{1*2}= 2*5 \to\boxed{10-choices}$