Question

If the molecules in the above illustration react to form NH3 according to the equation N2 3 H2 2 NH3 , the limiting reagent is , the number of NH3 molecules formed is , and the number of molecules in excess is

Answer 1

Answer:

Follows are the solution to these question:

Explanation:

Given equation:

$N_2+3H_2 \longrightarrow 2NH_3$

In this equation:

$1 N_2$ gives $= 2NH_3$

so,

$3N_2$ gives=  $2 \times 3 = 6 NH_3$

similarly:

$3H_2$ gives $= 2NH_3$

So, $6H_2$ gives = $\frac{2}{3}\times 6=4NH_3$

Its limited reagent is =$N_2$

The amount of $NH_3$ molecules were formed = 4.

and the amount of  $H_2$ excess molecules are= 1