a 100mh inductor is placed parallel with a 100 ohm resistor in the circuit , the circuit has a source voltage of 30 vac and a fr
1 answer:
Answer:
current through the inductor = 0.24 A
Explanation:
given data
inductor = 100mh
resistor = 100 ohm
voltage = 30 vac
frequancy = 200 Hz
to find out
current through the inductor
solution
current through the inductor will be when inductor is place parallel with resistor
across resistor
XL = i2πl
XL = i2π×200×100× = i126.66
so
current through the inductor =
current through the inductor =
current through the inductor = 0.24 A
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Answer:
The answer is "2 m/s".
Explanation:
The triangle from of the right angle:
Differentiating the above equation:
Answer:
q = 1.73 W
Explanation:
given data
small end = 5 cm
large end = 10 cm
high = 15 cm
small end is held = 600 K
large end at = 300 K
thermal conductivity of asbestos = 0.173 W/mK
solution
first we will get here side of cross section that is express as
...............1
here x is distance from small end and S1 is side of square at small end
and S2 is side of square of large end and L is length
put here value and we get
S = 5 +
S = m
and
now we get here Area of section at distance x is
area A = S² ...............2
area A = m²
and
now we take here small length dx and temperature difference is dt
so as per fourier law
heat conduction is express as
heat conduction q = ...............3
put here value and we get
heat conduction q =
it will be express as
now we intergrate it with limit 0 to 0.15 and take temp 600 to 300 K
solve it and we get
q (30) = (0.173) × (600 - 300)
q = 1.73 W
