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topjm [15]
4 years ago
14

2- A 2-m3 insulated tank containing ammonia at -20 C, 80% quality, is connected by a valve to a line flowing ammonia at 2 MPa, 6

0 C. The valve is opened, allowing ammonia to flow into the tank. At what pressure should the vale be closed if the manufacturer wishes to have 15 kg of ammonia inside at the final state?​
Engineering
1 answer:
alekssr [168]4 years ago
8 0

Answer:

The valve should be closed at 1081 kPa ⇒ 11 bar

Explanation:

Q_{C_V} + m_ih_i = m_2u_2 - m_1u_1 + W_{C_V}

Q_{C_V} = W_{C_V} = 0

m_1 = \frac{V}{v_1}  = \frac{2}{0.49927} = 4.006 kg

m_i = m_2 - m_1 = 15 - 4.006 = 10.994 kg

u_1 = 1057.5, h_i = 1509.9

u_2 =  m_ih_i + m_1u_1

m_2 = \frac{[10.994*1509.9] + [4.006*1057.5]}{15}  = 1389.1 kJ/kg

v_2 = \frac{V}{m_2} = \frac{2}{15} = 0.1333 m^3/kg

Therefore, v₂, u₂ fix state 2.  

​By trial and error, P₂ = 1081 kPa & T₂ = 50.4° C

1081 kPa ⇒ 11 bar

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Air pressure at the end of the Turbine exit is : 730.57 K

<u>Given data :</u>

Pressure ratio ( p₂ / p₁ )= 10.9

minimum temperature ( T₁ ) = 280 K

maximum temperature ( T₃ ) = 1410 K

Assuming :

constant specific heat and efficiency of 100%

<h3 /><h3>Determine the Air pressure at the end of the turbine exit </h3>

For air :

Cp = 1.005 kJ/kg.k,  Cv = 0.718 kJ/kg.k,  v = 1.4

Given that efficiency for compressor and turbine is 100% the process ( 1-2 , 3 - 4 ) will all be isentropic

We will Apply the formula below

\frac{T_{2} }{T_{1} } = ( \frac{p_{2} }{p_{1} } )^{\frac{v-1}{v} } = ( \frac{V_{1} }{V_{2} } )^{v-1}

Insert values into equation ( 1 )

T₂ = 551.147 K  ( temperature at compressor exit )

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<u>Next : Determine the </u><u>value </u><u>of the temperature at </u><u>Turbine exit </u><u>( T₄ )</u>

T₃ / T₄ = 10.7^^{\frac{1.4-1}{1.4} }

Therefore : T₄ = 1410 / 10.7^0.286

                        = 1410 / 1.93

                        = 730.57 K

Hence we can conclude that the Air pressure at the end of the Turbine exit is :  730.57 K .

Learn more about Turbine : brainly.com/question/894340

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The volume of a cylinder is to be determined from measurements of the diameter and length. If the length and diameter are measur
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Because the volume of the cylinder is gotten by measuring length and diameter of the cylinder, using a micrometer that has a 0.5% uncertainty, this will cause the measurements of each value to have a 0.5% uncertainty.

Therefore, since the length has 0.5% uncertainty and the diameter has 0.5% uncertainty too.

The uncertainty in the measurement will be.

0.5% + 0.5% = 1%

Since we are told that this measurement was carried out in four different locations, that means the uncertainty will become;

1% × 4 = 4%

As the number of locations increases, the uncertainty in the measurement will increase as well.

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Answer:

The two large divisions of heat exchangers are direct contact between fluids and indirect contact between fluids.

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A heat exchanger is one of the most used equipment at the level of thermal installations, both at the building, tertiary and industrial levels. A heat exchanger is a device designed to transfer heat between two fluids. These two fluids (liquids, gases) can be in contact or separated by a solid barrier. Its use is basic in all types of air conditioning or refrigeration, air conditioning, energy transfer or chemical processes. Heat transmission occurs through convection and conduction.

Classifying heat exchange systems can be carried out using many different criteria. When classifying different types of heat exchangers, different criteria can be taken into account. Taking into account the degree of contact between the fluids, they are grouped into two different types:

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Indirect Contact Heat Exchanger :

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Tech B is correct.

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