Answer:
18 kJ
Explanation:
Given:
Initial volume of air = 0.05 m³
Initial pressure = 60 kPa
Final volume = 0.2 m³
Final pressure = 180 kPa
Now,
the Work done by air will be calculated as:
Work Done = Average pressure × Change in volume
thus,
Average pressure = 
= 120 kPa
and,
Change in volume = Final volume - Initial Volume = 0.2 - 0.05 = 0.15 m³
Therefore,
the work done = 120 × 0.15 = 18 kJ
Answer:
insert (array[] , value , currentsize , maxsize )
{
if maxsize <=currentsize
{
return -1
}
index = currentsize-1
while (i>=0 && array[index] > value)
{
array[index+1]=array[index]
i=i-1
}
array[i+1]=value
return 0
}
Explanation:
1: Check if array is already full, if it's full then no component may be inserted.
2: if array isn't full:
- Check parts of the array ranging from last position of range towards initial range and determine position of that initial range that is smaller than the worth to be inserted.
- Right shift every component of the array once ranging from last position up to the position larger than the position at that smaller range was known.
- assign new worth to the position that is next to the known position of initial smaller component.
Answer:
Driving test
Explanation:
Usually according to laws in countries worldwide, to be licenced to drive, one is required to go through a driving school to learn the ethics and rules of driving.
Answer:
r=0.228m
Explanation:
The equation that defines the states of a gas according to its thermodynamic properties is given by the general equation of ideal gases
PV=nRT
where
P=pressure =5bar=500.000Pa
V=volume
n=moles=10
R = universal constant for ideal gases = 8.31J / (K.mol)
T=temperature=80F=299.8K
solvig For V
V=(nRT)/P
we know that the volume of a sphere is
solving for r
![r=\sqrt[3]{ \frac{3 V}{4\pi } }](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3%20V%7D%7B4%5Cpi%20%7D%20%7D)
solving
![r=\sqrt[3]{ \frac{3 (0.049)}{4\pi } }\\r=0.228m](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3%20%280.049%29%7D%7B4%5Cpi%20%7D%20%7D%5C%5Cr%3D0.228m)
