Answer:
The code will be:
#include <stdio.h>
#include <stdlib.h>
main () {
double weight, shippingCharge, rate, segments;
int distance;
printf("Enter the weight: \n");
scanf("%lf", &weight);
printf("Enter the distance: \n");
scanf("%i", &distance);
if (weight <= 10) {
printf("Rate is $3.00 \n");
rate = 3;
} else {
printf("Rate is $5.00 \n");
rate = 5;
}
if (distance % 500 == 0) {
segments = distance / 500;
} else {
segments = distance / 500 + 1;
}
shippingCharge = rate * segments;
if (distance >1000) {
shippingCharge = shippingCharge + 10;
}
printf("Your shipping charge is $%lf\n", shippingCharge);
system ("pause");
}
Answer:
a) 24 kg
b) 32 kg
Explanation:
The gauge pressure is of the gas is equal to the weight of the piston divided by its area:
p = P / A
p = m * g / (π/4 * d^2)
Rearranging
p * (π/4 * d^2) = m * g
m = p * (π/4 * d^2) / g
m = 1200 * (π/4 * 0.5^2) / 9.81 = 24 kg
After the weight is added the gauge pressure is 2.8kPa
The mass of piston plus addded weight is
m2 = 2800 * (π/4 * 0.5^2) / 9.81 = 56 kg
56 - 24 = 32 kg
The mass of the added weight is 32 kg.
AnswerWhat Are the Classifications of Burns? Burns are classified as first-, second-, or third-degree, depending on how deep and severe they penetrate the skin's surface. First-degree burns affect only the epidermis, or outer layer of skin. The burn site is red, painful, dry, and with no blisters.
Explanation:
Answer:
ω=314.15 rad/s.
0.02 s.
Explanation:
Given that
Motor speed ,N= 3000 revolutions per minute
N= 3000 RPM
The speed of the motor in rad/s given as
Now by putting the values in the above equation
ω=314.15 rad/s
Therefore the speed in rad/s will be 314.15 rad/s.
The speed in rev/sec given as
ω= 50 rev/s
It take 1 sec to cover 50 revolutions
That is why to cover 1 revolution it take
