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has greater effect.
<u>Explanation</u>:

= Temperature of cold reservoir
= Temperature of hot reservoir
when
is decreased by 't',
= 

when
is increased by 'T'


Answer:
It is a non profit organization that dedicates to licensing professional engineers and surveyors
Explanation:
I think because if you’ve already turned it in they might as well grade asap instead of waiting
Answer:
14.506°C
Explanation:
Given data :
flow rate of water been cooled = 0.011 m^3/s
inlet temp = 30°C + 273 = 303 k
cooling medium temperature = 6°C + 273 = 279 k
flow rate of cooling medium = 0.02 m^3/s
Determine the outlet temperature
we can determine the outlet temperature by applying the relation below
Heat gained by cooling medium = Heat lost by water
= ( Mcp ( To - 6 ) = Mcp ( 30 - To )
since the properties of water and the cooling medium ( water ) is the same
= 0.02 ( To - 6 ) = 0.011 ( 30 - To )
= 1.82 ( To - 6 ) = 30 - To
hence To ( outlet temperature ) = 14.506°C