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olga_2 [115]
2 years ago
15

The regulator is closed when the adjusting screw is turned in (clockwise).

Engineering
1 answer:
lana66690 [7]2 years ago
4 0
False. Regulator adjusting screws should be turned counterclockwise.
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The relatonship between Kalven and celsius______
umka2103 [35]

Answer:

K=C+273.15

Explanation:

Kelvin's climbing represents the <em>absolute temperature</em>. Temperature is a measure of the molecular kinetic energy of translation. If the molecules move quickly, with the same energy as in the walls of the container, which makes us feel like "heat". If the molecules do not move, the temperature is zero. 0 K.

The Celsius scale has an <em>artificial zero</em>, defined in the solidification temperature of the water. It is very useful to talk about the weather, and about some simpler technical matters. But it is artificial.

3 0
4 years ago
Both portions of the rod ABC are made of an aluminum for whichE = 70 GPa. Knowing that the magnitude of P is 4 kN, determine(a)
san4es73 [151]

Explanation:

ΔL_{BC} = ΔL_{AB}

\frac{(Q - 4000)(0.5)}{3.14* 0.03 *0.03 *70*10^{9} }     (1)

= \frac{4000*0.4}{3.14*0.01*0.01*70*10^{9} }

Q = 32,800 N

now put this value in equation 1.

Deflection of B = \frac{(32800-4000)(0.5)}{3.14*0.03*0.03*70*10^{9} }

                       = 0.0728 mm

4 0
4 years ago
A shipment of rebar that weighs 745 kg would weigh roughly how much in pounds​
Andre45 [30]

Answer:

Dont no but will check

Explanation:

6 0
3 years ago
What is the base unit in standard measurement
Stella [2.4K]

Answer:

Explanation:SI is the base unit for standard measurement

7 0
3 years ago
Read 2 more answers
An electrical current of 700 A flows through a stainlesssteel cable having a diameter of 5 mm and an electricalresistance of 610
KatRina [158]

Answer:

778.4°C

Explanation:

I = 700

R = 6x10⁻⁴

we first calculate the rate of heat that is being transferred by the current

q = I²R

q = 700²(6x10⁻⁴)

= 490000x0.0006

= 294 W/M

we calculate the surface temperature

Ts = T∞ + \frac{q}{h\pi Di}

Ts = 30+\frac{294}{25*\frac{22}{7}*\frac{5}{1000}  }

Ts=30+\frac{294}{0.3928} \\

Ts =30+748.4\\Ts = 778.4

The surface temperature is therefore 778.4°C if the cable is bare

6 0
3 years ago
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