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konstantin123 [22]
2 years ago
14

Select the correct answer from each drop-down menu.

Physics
2 answers:
ElenaW [278]2 years ago
7 0

Answer:

The force of the (attraction) between the poles B and C is (maximum) and the force of a (attraction) between the poles A and D is (minimum).

Explanation:

-Dominant- [34]2 years ago
4 0

Answer:

And the force of ( Attraction or repulsion) between the poles A and D ( maximum or minimum)

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John walks 1.00 km north, then turns right and walks 1.00 km east. His speed is 1.50 m/s during the entire stroll.a) What is the
avanturin [10]

Answer:

(a) 1.414 km

(b) 1.06 m/s

Explanation:

(a) For John:

Distance = 1 km north and then 1 km east

Speed = 1.5 m/s

total distance traveled = 1 + 1 = 2 km = 2000 m

Time taken to travel = Distance / speed

t = 2000 / 1.5 = 1333.3 seconds

Displacement = \sqrt{1^{2}+1^{2}}=1.414 km

(b) For jane :

Time is same as john = 1333.33 second

Distance = 1.414 km = 1414 m

Speed = distance / time = 1414 / 1333.33 = 1.06 m/s

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3 years ago
Stars within the halo move in random orbits that extend above and below the disk of the galaxy, while stars in the disk move in
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<span>Answer: Spherical Distribution Feedback: Correct The stars in the halo component have highly-inclined random orbits that orbit the center of our Galaxy. The stars within the halo would therefore make up a spherical distribution of stars surrounding the center of the Galaxy. In comparison, the disk stars move in elliptical orbits, which are nearly circular and are confined to the disk of the Galaxy. Disk stars therefore have very small inclinations and do not move above or below the plane of the Galactic disk.</span>
4 0
3 years ago
What is normal for a spring that obeys hook's law ?
Bezzdna [24]
A spring that obeys Hooke's law has a spring force constant of 272 N/m. This spring is then stretched by 28.6 cm
7 0
3 years ago
Read 2 more answers
Three materials, put them in order of what
Grace [21]

Answer:

it's a

Explanation:

hope this helps!!!!!!

4 0
2 years ago
A total Δν of 15 km/s is required to achieve an interplanetary mission. The proposed rocket has two stages. The first stage alon
AlexFokin [52]

Answer:

102000 kg

Explanation:

Given:

A total Δν = 15 km/s

first stage mass = 1000 tonnes

specific impulse of liquid rocket =  300 s

Mass flow rate of liquid fuel = 1500 kg/s

specific impulse of solid fuel = 250 s

Mass flow of solid fuel = 200 kg/s

First stage burn time = 1 minute = 1 × 60 seconds = 60 seconds

Now,

Mass flow of liquid fuel in 1 minute = Mass flow rate × Burn time

or

Mass flow of liquid fuel in 1 minute = 1500 × 60 = 90000 kg

Also,

Mass flow of solid fuel in 1 minute = Mass flow rate × Burn time

or

Mass flow of solid fuel in 1 minute = 200 × 60 = 12000 kg

Therefore,

The total jettisoned mass flow of the fuel in first stage

= 90000 kg +  12000 kg

= 102000 kg

3 0
3 years ago
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