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SCORPION-xisa [38]
3 years ago
13

According to Newton’s Third Law, action and reaction are

Physics
2 answers:
Grace [21]3 years ago
6 0
Newtons third law is that for every action there is an eqaul and opposite reaction
Komok [63]3 years ago
5 0
<span>B. equal and in opposite directions</span>
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Someone please help me
Lapatulllka [165]
False... I hope that helps ;)
6 0
3 years ago
The force of attraction between a -165.0 uC and +115.0 C charge is 6.00 N. What is the separation between these two charges in m
Molodets [167]

Answer:

r = 5.335 meters

Explanation:

Given that,

Charge 1, q_1=-165\ \mu C

Charge 2, q_2=115\ \mu C

Force of attraction between two charges, F = 6 N

The force of attraction between two charges is given by :

F=k\dfrac{q_1q_2}{r^2}, r is the separation between two charges

r=\sqrt{\dfrac{kq_1q_2}{F}}

r=\sqrt{\dfrac{9\times 10^9\times 165\times 10^{-6}\times 115\times 10^{-6}}{6}}

r = 5.335 m

So, the separation between two charges is 5.335 meters. Hence, this is the required solution.

6 0
3 years ago
How does an acid–base indicator react when placed in an acidic solution?
s344n2d4d5 [400]
It depends on the indicator, and the pH range over which it will experience a colour change. Some indicators will change colour<span> in an acidic solution, others will not. For example, blue litmus paper will turn red in an acidic solution, but red litmus paper will not change colour. The test would be inconclusive with red litmus paper, since it does not change colour in an acid and in a neutral solution.</span>
3 0
4 years ago
When balanced forces act on an object, what type of motion can the object have?
Lesechka [4]

Answer: A. It can only be motionless.

Explanation: When balanced forces act on an object, the object will not move. The only way that object can move is if the forces become unbalanced. Suppose there is a shoe on a table. You are pulling back on the shoe with a force of 3 newtons. But the friction from the shoe rubbing on the table is also 3 newtons of force. But the gravity pulling down on the shoe is also 3 newtons. Nothing will move. The only way the shoe can move is if you pulled with a little more force. The shoe would then move because the force you are pulling with is greater than the other forces acting on the shoe.

Ex 2: You are playing tug of war. Team a is pulling with 20 Newtons of force. Team b is also pulling with 20 newtons of force. The rope does not move. Team a starts to pull a little harder. Now they are pulling with 25 Newtons of force. Now the rope starts moving their way.

8 0
3 years ago
A brick lands 10.1 m from the base of a building. If it was given an initial velocity of 8.6 m/s [61º above the horizontal], how
Montano1993 [528]
<h2>Answer: 10.52m</h2><h2 />

First, we have to establish the <u>reference system</u>. Let's assume that the building is on the negative y-axis and that the brick was thrown at the origin (see figure attached).

According to this, the initial velocity V_{o} has two components, because the brick was thrown at an angle \alpha=61\º:

V_{ox}=V_{o}cos\alpha   (1)

V_{ox}=8.6\frac{m}{s}cos(61\º)=4.169\frac{m}{s}  (2)

V_{oy}=V_{o}sin\alpha   (3)

V_{oy}=8.6\frac{m}{s}sin(61\º)=7.521\frac{m}{s}   (4)

As this is a projectile motion, we have two principal equations related:

<h2>In the x-axis: </h2>

X=V_{ox}.t  (5)

Where:

X=10.1m is the distance where the brick landed

t is the time in seconds

If we already know X and V_{ox}, we have to find the time (we will need it for the following equation):

t= \frac{X}{ V_{ox}}  (6)

t=2.42s  (7)

<h2>In the y-axis: </h2>

-y=V_{oy}.t+\frac{1}{2}g.t^{2}   (8)

Where:

y is the height of the building (<u>in this case it has a negative sign because of the reference system we chose)</u>

g=-9.8\frac{m}{s^{2}} is the acceleration due gravity

Substituting the known values, including the time we found on equation (7) in equation (8), we will find the height of the building:

-y=(7.521\frac{m}{s})(2.42s)+\frac{1}{2}(-9.8\frac{m}{s^{2}}).(2.42s)^{2}   (9)

-y=-10.52m   (10)

Multiplying by -1 each side of the equation:

y=10.52m >>>>This is the height of the building

3 0
3 years ago
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