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4 years ago

10 4/5 + (8 3/4 − 6 1/2)

Mathematics

1 answer:

Bad White [126]4 years ago

4 0

Answer:

261/20

Step-by-step explanation:

=54/5+(35/4-13/2)

= 54/5+9/4

=261/20

You can use calculator. It's easier.

You might be interested in

Graph f(x) =-2x^+16x-30 by factoring to find the solutions, then find the coordinates of the vertex, and the axis of symmetry. I

fredd [130]

Answer:

Observe attached image

Function zeros:

(3, 0), (5, 0)

Vertex:

(4, 2)

Axis of symmetry:

 $x =4$ 

Step-by-step explanation:

First factorize the function

$f (x) = -2x ^ 2 + 16x-30$

Take -2 as a common factor.

$-2(x ^ 2 -8x +15)$

Now factor the expression $x ^ 2 -8x +15$

You must find two numbers that when you add them, obtain the result -8 and multiplying those numbers results in 15.

These numbers are -5 and -3

Then we can factor the expression in the following way:

$f (x) = -2(x-5)(x-3)$

The quadratic function cuts the x-axis at x = 3 and at x = 5.

Now we find the coordinates of the vertex.

For a function of the form $ax ^ 2 + bx + c$ the x coordinate of its vertex is:

$x = \frac{-b}{2a}$

In the function $f (x) = -2x ^ 2 + 16x-30$

$a = -2\\b = 16\\c = 30$

Then the vertice is:

$x = \frac{-16}{2(-2)}\\\\x = 4$

The y coordinate of the symmetry axis is

$y = f (4) = -2 (4) ^ 2 +16 (4) -30\\\\y = 2$

The axis of symmetry is a vertical line that cuts the parabola in two equal halves. This axis of symmetry always passes through the vertex.

Then the axis of symmetry is the line

$x = 4$

The solutions and the vertice written as ordered pairs are:

Function zeros:

(3, 0), (5, 0)

Vertex:

(4, 2)

6 0

3 years ago

You have a credit card with a balance of $754.43 at a 13.6% APR. You have $300.00 available each month to save or pay down your

pochemuha

B(n) = A(1 + i)^n - (P/i)[(1 + i)^n - 1]

where B is the balance after n payments are made, i is the monthly interest rate, P is the monthly payment and A is the initial amount of loan.

We require B(n) = 0...i.e. balance of 0 after n months.

so, 0 = A(1 + i)^n - (P/i)[(1 + i)^n - 1]

Then, with some algebraic juggling we get:

n = -[log(1 - (Ai/P)]/log(1 + i)

Now, payment is at the beginning of the month, so A = $754.43 - $150 => $604.43

Also, i = (13.6/100)/12 => 0.136/12 per month

i.e. n = -[log(1 - (604.43)(0.136/12)/150)]/log(1 + 0.136/12)

so, n = 4.15 months...i.e. 4 payments + remainder

b) Now we have A = $754.43 - $300 = $454.43 so,

n = -[log(1 - (454.43)(0.136/12)/300)]/log(1 + 0.136/12)

so, n = 1.54 months...i.e. 1 payment + remainder

8 0

3 years ago

What is the product of − 3/11 and − 2/15? please explain.

emmainna [20.7K]

ANSWER

The product is

$\frac{2}{55}$

EXPLANATION

To find the product of

$- \frac{3}{11}$

and

$\frac{ - 2}{15}$

means we should multiply the two fractions.

We multiply to obtain,

$- \frac{3}{11} \times - \frac{2}{15}$

$= - \frac{3}{11} \times - \frac{2}{3 \times 5}$

Cancel the common factors:

$= - \frac{1}{11} \times - \frac{2}{5}$

Now, multiply the numerators separately and the denominators too separately.

$= \frac{ - 1 \times - 2}{11 \times 5}$

This simplifies to,

$= \frac{2}{55}$

4 0

3 years ago

Image point B (4,-8) was transformed using the translation (x-2,y+3) what were the coordinates of B?

PilotLPTM [1.2K]

The coordinates of the image point are given to be B(4, -8). We are to find the coordinates of pre-image that is the coordinates before the translation.

The translation made was (x-2, y+3)

This means, the x coordinate was moved 2 units to left and y coordinate was moved 3 units above.

So, the coordinates of original point will be, 2 units to right of B and 3 units down of B.

So the coordinates will be (6, -11)

5 0

3 years ago

Read 2 more answers

For each explicitly-defined sequence below, write the first few terms. Then use the terms to write a recursive equation.

julia-pushkina [17]

Answer:

Step-by-step explanation:

Problem A

t(1) = 2(1) + 5

t(2) = 2*2 + 5 = 9

t(3) = 2*3 + 5 = 11

t(4) = 2*4 + 5 = 13

So this is the explicit result. Now try it recursively.

t_3 = t_2 + 2

t_3 = 9 + 2

t_3 = 11 which is just what it should do.

t_n = t_(n - 1) + 2

Problem B

t(1) = 3 * 1/2

t(1) = 3/2

t(2) = 3*(1/2)^2

t(2) = 3 * 1/4

t(2) = 3/4

t(3) = 3*(1/2)^3

t(3) = 3 * 1/8

t(3) = 3/8

t(4) = 3 (1/2)^4

t(4) = 3 (1/16)

t(4) = 3/16

So in general

t_n = t_n-1 * 1/2

For example t(5)

t_5 = t_4 * 1/2

t_5 = 3 /16 * 1/2 = 3/32

6 0

3 years ago