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3 years ago

5. The condition of the road surface affects total stopping distance.A. trueB. false

Physics

1 answer:

Tom [10]3 years ago

7 0

Answer:

A true

Explanation:

Can you please give me brainiest.

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A bug is sitting on the edge of a rotating disk. At what angular velocity will the bug slide off the disk if its radius is 0.241

Ivahew [28]

Answer:

ω = 3.61 rad/sec

Explanation:

Firstly, we should know that the bug will not slip if friction can provide sufficient opposing force.

μmg = mv^2/r = mω^2r

Thus;

μg = ω^2r

ω^2 = μg/r

ω = √(μg/r)

ω = √(0.321 * 9.8)/0.241

ω = √(13.05)

= 3.61 rad/sec

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3 years ago

TRUE OR FALSE: The following drops were most likely dropped from a 90 degree angle.

horsena [70]

Answer:

True

Explanation:

If it weren't from a 90 degree angle then the circle would be a bit more oval shaped

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3 years ago

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A proposed ocean thermal-energy conversion (OTEC) system is a heat engine that would operate between warm water (16°C) at the oc

LenaWriter [7]

Answer:

$3.46$ %

Explanation:

We have given cooler temperature that is $T_c$ = 6°C =273+6=279 K

And the warm temperature of water that is $T_h=16^{\circ}C=16+273=289\ K$

The maximum possible efficiency is given by $\eta =1-\frac{T_c}{T_h}$

So maximum efficiency $\eta =1-\frac{T_c}{T_h}=1-\frac{279}{289}=0.0346=3.46$ %

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2 years ago

Which car has the most kinetic energy ??

gregori [183]

Kinetic Energy is defined by 1/2 times the mass times the velocity squared.

KE = (1/2)mv2

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3 years ago

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A brick falls to the ground. if the time for the collision of the brick and the ground is increased by a factor of 4, the force

melomori [17]

Answer:

By a factor of 1/4.

Explanation:

The impulse force that applies to an object undergoing rapid deceleration just before coming to a stop on the ground is given by the following formula,

$\\\begin{aligned}\\\small F &=\small \frac{\Delta (mV)}{\Delta T}\end{aligned}$

in which $\small \Delta (mV)$ , $\small \Delta t$ represent the change in momentum and the time taken for that change.

If one increases the time that is taken for the momentum change (which remains constant for this situation) by a factor 4 and if that new force is represented by $\small F_1$ , the following manipulation confirms the answer to this question.

$\begin{aligned}\\\small F_1 &=\small \frac{\Delta (mV)}{4\Delta t}\\\\&=\small \frac{1}{4}\times\bigg[\frac{\Delta (mV)}{\Delta t}\bigg]\\\\&=\small \frac{1}{4}F\end{aligned}$

Here $\small F$ is the force that was applied to the object previously.

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1 year ago

5. The condition of the road surface affects total stopping distance.A. trueB. false​

5. The condition of the road surface affects total stopping distance.A. trueB. false