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Nata [24]
3 years ago
7

Isoflurane, shown here, is a common inhalation anesthetic. write its molecular formula and calculate its percent composition by

mass
Chemistry
1 answer:
Natalka [10]3 years ago
7 0

Molecular formula of Isoflurane is <span><span>C</span></span>₃H₂ClF₅O.

Now calculate the percent composition by mass, which means percent of each element in the compound.

Mass of Isoflurane = 184.49 g/mol

Mass of carbon in the compound = 3 x 12.011 = 36.033g

Mass of hydrogen in the compound = 2 x 1.008 = 2.016g

Mass of chlorine in the compound = 1 x 35.453 = 35.453 g

Mass of fluorine in the compound = 5 x 18.998 = 94.99g

Mass of Oxygen in the compound = 1 x 16 = 16 g

Carbon’s percentage = Mass of carbon in the compound /mass of isoflurane x 100 =36.033/184.49 x 100 =19.53%

Hydrogen’s Percentage = Mass of hydrogen in the compound/mass of isoflurane x 100 = 2.016/184.49 = 1.09%

Chlorine’s percentage = Mass of chlorine in the compound/mass of isoflurane x 100 = 35.453/184.49 =19.22%

Flourine’s percentage = Mass of fluorine in the compound/mass of isoflurane x 100 = 94.99/184.49 x 100 = 51.49%

Oxygen’s percentage = Mass of Oxygen in the compound/mass of isoflurane x 100 =16/184.49 x 100 = 8.67%

<span> </span>

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3 years ago
Find the number of moles of argon in 364 grams of argon.
serg [7]

Answer:D. 9.1 mole Ar

Explanation:

364 g Ar x 1 mole Ar / 40 g Ar

= 9.1 moles Ar

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What is Chemistry and how do you relate in real life?
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Another carbon isotope has six protons and seven neutrons in its nucleus. What do you think this carbon isotope is called?
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Carbon - 13

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For most of the elements other than that of hydrogen, the isotopes are named for the mass number.

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Baking soda (NaHCO3) and vinegar (HC2H3O2) react to form sodium acetate, water, and carbon dioxide. If 42.00 g of baking soda re
Setler [38]

Answer:

0.5 mole of CO₂.

Explanation:

We'll begin by calculating the number of mole in 42 g of baking soda (NaHCO₃). This can be obtained as follow:

Mass of NaHCO₃ = 42 g

Molar mass of NaHCO₃ = 23 + 1 + 12 + (16×3)

= 23 + 1 + 12 + 48

= 84 g/mol

Mole of NaHCO₃ =?

Mole = mass / molar mass

Mole of NaHCO₃ = 42/84

Mole of NaHCO₃ = 0.5 mole

Next, balanced equation for the reaction. This is given below:

NaHCO₃ + HC₂H₃O₂ → NaC₂H₃O₂ + H₂O + CO₂

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of CO₂

Finally, we shall determine the number of mole of CO₂ produced by the reaction of 42 g (i.e 0.5 mole) of NaHCO₃. This can be obtained as follow:

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of CO₂.

Therefore, 0.5 mole of NaHCO₃ will also react to produce 0.5 mole of CO₂.

Thus, 0.5 mole of CO₂ was obtained from the reaction.

7 0
3 years ago
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