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lyudmila [28]
3 years ago
8

Se deja caer un objeto desde la cornisa de una casa la cual tarda en llegar al suelo 645/500 segundos. ¿Cúal es la altura de la

casa?
Physics
1 answer:
salantis [7]3 years ago
4 0

8.15m. La altura de la casa de la cual se deja caer un objeto que tarda en caer \frac{645}{500}s es de 8.15m.

La clave para resolver este problema es mediante caída libre, la velocidad inicial del objeto es 0 por lo que podemos calcular la altura h de la casa mediante la relación h= \frac{gt^{2}}{2}.

Conocemos la gravedad g=9.8\frac{m}{s^{2}} y el tiempo en que tarda en caer el objeto t=\frac{645}{500}s, sustituyendo los valores tenemos que:

h=\frac{(9.8\frac{m}{s^{2}})(\frac{645}{500}s)^{2}}{2}=8.15m

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Q = U_{l,ice} + U_{s, w} + U_{s,ice} + U_{l,steam} (1)

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h_{v,w} - Latent heat of vaporization of water, in joules per kilogram.

c_{ice} - Specific heat of ice, in joules per kilogram per degree Celsius.

c_{w} - Specific heat of water, in joules per kilogram per degree Celsius.

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\Delta T_{w} - Change in temperature of water, measured in degrees Celsius.

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