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3 years ago

PLEASE HELP WILL GIVE BRAINLIEST!!! DUE SOON!! GIVE ME 2 REASONS WHY

Physics

2 answers:

TiliK225 [7]3 years ago

6 0

Answer:

★ For example, cold water has a higher density than warmer water. In Addition, water gets colder with depth because of the coldness, of the salty ocean water which sinks to the bottom of the ocean basins below the less dense water near the surface

Explanation:

Hope you have a great day :)

BartSMP [9]3 years ago

4 0

Cold water has a higher density than watm water. water gets colder with depth because of the cold, salty ocean water sinks to the bottom of the ocean basins below the less dense water near the surface

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The most common units for expressing the density of a substance are the g/cm3.

Luden [163]

True.

Density = mass / volume, Unit = g / cm³.

This is a common unit because of its affiliation with the SI unit and because that also our popular liquid which is water = 1 g/cm³

6 0

3 years ago

Am I correct?? Will give brainliest

Anna35 [415]

Yes that looks correct to me. good luck!!

5 0

3 years ago

An electron with charge −e and mass m moves in a circular orbit of radius r around a nucleus of charge Ze, where Z is the atomic

shepuryov [24]

Answer:

$v=\sqrt{\frac{kZe^2}{mr}}$

Explanation:

The electrostatic attraction between the nucleus and the electron is given by:

$F=k\frac{(e)(Ze)}{r^2}=k\frac{Ze^2}{r^2}$ (1)

where

k is the Coulomb's constant

Ze is the charge of the nucleus

e is the charge of the electron

r is the distance between the electron and the nucleus

This electrostatic attraction provides the centripetal force that keeps the electron in circular motion, which is given by:

$F=m\frac{v^2}{r}$ (2)

where

m is the mass of the electron

v is the speed of the electron

Combining the two equations (1) and (2), we find

$k\frac{Ze^2}{r^2}=m\frac{v^2}{r}$

And solving for v, we find an expression for the speed of the electron:

$v=\sqrt{\frac{kZe^2}{mr}}$

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2 years ago

At what distance will the weight of a body be halved , Earth's radius=6.4×10^6

Sholpan [36]

A body of mass m has weight

F = GMm/r²

on the surface of the Earth, where G is the universal gravitational constant, M is the mass of the Earth, and r is it's radius.

If the weight is to be halved, then we have

1/2 F = 1/2 GMm/r² = (1/√2)² GMm/r² = GMm/(√2 r²)

so the distance between the body and the planet's center needs to be

√2 × 6.4 × 10⁶ m ≈ 9.1 × 10⁶ m

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3 years ago

Which of the following is NOT an important factor in selecting a medical professional?

lara31 [8.8K]

Answer:

Explanation:

appearance is not a imp factor . location could be imp. becoz a proper environment is need to study such courses.

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3 years ago