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3 years ago

Which describes the path of a gas particle between collisions with other particles

Physics

2 answers:

Ghella [55]3 years ago

6 0

A.Spiral

B.Random

C.Zigzag line

D.Straight line

Straight line

netineya [11]3 years ago

3 0

As gas particles are in constant motion, it exhibit perfect elastic collisions with other particles and travel in straight line in complicated paths. According to Kinetic Molecular Theory, gas is modeled as a collection of gas particles that are colliding frequently with one another and with the walls of the container but no energy is lost during the collision.

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The moon is 3x10^5 km away from Nepal and the mass of the moon is 7x10^22 kg. Calculate the force with which the Moon pulls ever

hammer [34]

Answer:

Approximately $5.19 \times 10^{-5}\; \rm N$ .

Explanation:

Let $G$ denote the gravitational constant. ( $G \approx 6.67 \times 10^{-11} \; \rm N \cdot kg^{-2} \cdot m^{2}$ .)

Let $M$ and $m$ denote the mass of two objects separated by $r$ .

By Newton's Law of Universal Gravitation, the gravitational attraction between these two objects would measure:

$\displaystyle F = \frac{G \cdot M \cdot m}{r^{2}}$ .

In this question: $M = 7 \times 10^{22}\; \rm kg$ is the mass of the moon, while $m = 1\; \rm kg$ is the mass of the water. The two are $r = 3\times 10^{5}\; \rm km$ apart from one another.

Important: convert the unit of $r$ to standard units (meters, not kilometers) to reflect the unit of the gravitational constant $G$ .

$\displaystyle r = 3 \times 10^{5}\; \rm km \times \frac{10^{3}\; \rm m}{1\; \rm km} = 3 \times 10^{8}\; \rm m$ .

$\begin{aligned} F &= \frac{G \cdot M \cdot m}{r^{2}} \\ &= \frac{6.67 \times 10^{-11}\; \rm N \cdot kg^{-2}\cdot m^{2} \times 7 \times 10^{22}\; \rm kg \times 1\; \rm kg}{(3 \times 10^{8}\; \rm m)^{2}} \\ &\approx 5.19 \times 10^{-5} \; \rm N\end{aligned}$ .

5 0

3 years ago

On her camping trip, Penelope was in charge of collecting firewood. The firewood she found had a mass of 120 g and a volume of 4

zloy xaker [14]

From the formula: density=mass/volume
But first, we have to convert the cm³ to m³ by multiplying the value in cm³ by 10^-6, by so doing we'll have the volume to be 0.48*10^-3cm³.
we will also need to convert the mass which is in g to kg by simply dividing by 1000 so the mass becomes 0.12kg
Now we can solve for the density using the formula I earlier stated which is the mass divided by the volume =0.12/0.48*10^-3 so the density will be 0.25*10^3kgm-3 or 2.5*10^2kgm-3

3 0

3 years ago

Differentiate between: a. Compression and Rarefaction

zlopas [31]

Answer:

Explanation:

Compression

The region in a medium where the distance between the vibrating molecules is minimum is compression.

This is the region with higher air pressure than the surrounding .

Rarefaction

The region in a medium where the distance between the vibrating molecules is maximum is rarefaction.

This is the region with relatively low air pressure.

hope it helps :)

7 0

3 years ago

The first law of thermodynamics states that E=Q-W. How is this also a statement of the principle of conservation of energy?

g100num [7]

This law demonstrates that the energy within a close system may be converted from one form to another, but it cannot be created nor destroyed.

4 0

3 years ago

An implanted pacemaker supplies the heart with 72 pulses per minute, each pulse providing 6.0 V for 0.65 ms. The resistance of t

Firlakuza [10]

Answer:

a) Current = 11 mA

b) Energy = 66 mJ

c) Power = 101.54 W

Explanation:

a) Voltage, V = IR

Voltage, V = 6 V, Resistance, R = 550 Ω

Current, I $=\frac{6}{550}=0.011A=11mA$

b) Energy = Current x Voltage = 6 x 0.011 = 0.066 J = 66 mJ

c) $\texttt{Power=}\frac{Energy}{Time}=\frac{0.066}{0.65\times 10^{-3}}=101.54W$

6 0

3 years ago