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4 years ago

A 100 V battery is connected across a

Physics

1 answer:

Sergio039 [100]4 years ago

5 0

1 mA = 0.001 A

Therefore, 5 mA = 0.001 * 5

=0.005 A

Resistance = voltage / current

= 100 / 0.005

= 20000 ohms

Current = voltage / resistance

= 25 / 20000

= 0.00125 A (or) 1.25 mA

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Which characteristic of a sound is affected by the amount of energy used to create that sound? In what direction the sound will

olya-2409 [2.1K]

Answer:

The correct option is;

How loud or soft the sound is

Explanation:

The loudness of a sound wave is given by the amount of energy that the pressure wave carries and it is measured in decibels (dB) which is the relative intensity of the pressure wave of a sound to the standard pressure

A loud sound has a high amplitude and a soft sound has a low amplitude, such that as the amplitude of the sound is increased, due to increased energy input, the sound becomes louder, and as the amplitude of the sound is decreased due to reduced energy input, the sound becomes softer.

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3 years ago

Organ systems are groups of organs that do not carry out similar<br> functions <br> True<br> False

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Answer:

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3 years ago

If an object is pushed with 10 newtons to the right but friction slows down the object with 5 newtons to the left and a person p

Natasha_Volkova [10]

Yes they are balanced because if it has 10 Newtons to the right and then someone pushes 5 Newtons to the left and then another 5 then that means there is 10 Newtons left and 10 Newtons right

4 0

3 years ago

Please solve this problem inelastic collision

S_A_V [24]

It will crash at a speed of 5 m/s and that's basically it.

7 0

4 years ago

El monoxido de carbono reacciona con el hidrogeno gaseoso para producir metanol (ch3oh) calcule el reactivo limite y el reactivo

Orlov [11]

Answer:

Se obtienen 2,27 gramos de metanol.

Explanation:

La reacción entre monóxido de carbono e hidrógeno para producir metanol es la siguiente:

CO + 2H₂ → CH₃OH

Para encontrar el reactivo limitante y el reactivo en exceso, debemos calcular el número de moles de CO y H₂:

$\eta_{CO} = \frac{m}{M}$

En donde:

m: es la masa

M: es el peso molecular

$\eta_{CO} = \frac{m}{M_{CO}} = \frac{2,0 g}{28,01 g/mol} = 0,071 moles$

$\eta_{H_{2}} = \frac{2,0 g}{2,02 g/mol} = 0,99 moles$

Dado que la relación estequiométrica entre CO y H₂ es 1:2, el número de moles de hidrógeno gaseoso que reaccionan con el monóxido de carbono es:

$\eta_{H_{2}} = \frac{2}{1}*0,071 = 0,142 moles$

Entonces, se necesitan 0,142 moles de H₂ para reaccionar con 0,071 moles de CO y debido a que se tienen más moles de H₂ (0,99 moles) entonces el reactivo limitante es CO y el reactivo en exceso es H₂.

Ahora podemos encontar la masa de metanol obtenida usando el reactivo limitante (CO) y sabiendo que la realcion estequiométrica entre CO y CH₃OH es 1:1.

$\eta_{CH_{3}OH} = \eta_{CO} = 0,071 moles$

$m = 0,071 moles*32,04 g/mol = 2,27 g$

Por lo tanto, se obtienen 2,27 gramos de metanol.

Espero que te sea de utilidad!

6 0

3 years ago