Answer:
8.55x10^22 molecules
Explanation:
From the question given, the following data were obtained:
Density = 1g/mL
Volume = 2.56mL
Mass =?
Density = Mass /volume
Mass = Density x volume
Mass = 1 x 2.56
Mass = 2.56g
Now let us convert this mass (i.e 2.56g) of water to mole
Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol
Mass of H2O = 2.56g
Number of mole of H2O=? Number of mole = Mass /Molar Mass
Number of mole of H2O = 2.56/18
Number of mole of H2O = 0.142mol
From Avogadro's hypothesis, 1mole of any substance contains 6.02x10^23 molecules. This means that 1mole of H2O contains 6.02x10^23 molecules.
Now if 1mole of H2O contains 6.02x10^23 molecules, then 0.142mol of H2O will contain = 0.142 x 6.02x10^23 = 8.55x10^22 molecules
Answer:
<h2>7.65 litres </h2>
Explanation:
The new volume can be found by using the formula for Boyle's law which is
Since we're finding the new volume
15 kPa = 15,000 Pa
50 kPa = 50,000 Pa
We have
We have the final answer as
<h3>7.65 litres </h3>
Hope this helps you
Greetings!
To find the empirical formula you need the relative atomic mass of each element!
Li = 6.9
C = 12
O = 16
You can simply change the percentages into full grams
Li = 18.8g
C = 16.3g
O = 64.9
Then you use this to find the Number of moles = amount in grams / atomic mass
Li = 18.8 ÷ 6.9 = 2.7246
C = 16.3 ÷ 12 = 1.3583
O = 64.9 ÷ 16 = 4.0562
Then divide each number of moles by the smallest value:
Li = 2.7246 ÷ 1.3583 = 2.0
C = 1.3583 ÷ 1.3583 = 1
O = 4.0562 ÷ 1.3583 = 2.9 ≈ 3
So that means that there are 2 Li, 1 C, and 3 O
Empirical formula would be:
Li₂CO₃
Hope this helps!
