A race car moves such that its position fits

1 answer:

5 0

Approximate the instantaneous velocity by computing the average velocity of the car over the interval [1.95, 2.05] (i.e. the interval centered at t = 2 s with length 0.1 s).

By definition, average velocity is given by

v = ∆x / ∆t

So we have

v(2 s) ≈ (x(2.05 s) - x(1.95 s)) / (0.1 s) ≈ 13.94 m/s

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12. A cross-country race car driver sets out on a 1.00 hour, 100.0 km race. At the halfway marker

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Answer:

A.) Time = 0.625 hrs = 37.5 minutes

B.) Speed required = 133.33km/hr

Explanation:

Given the following :

Total race distance = 100km

Total time required = 1 hour = 60 minutes

Average speed after traveling 50km = 80km/hr

80km/hr : This means it will take one hour to cover a distance of 80km

Therefore, time taken to cove first 50km at that average speed equals :

1 hour = 80 km

t hours = 50km

80t = 50

t = 50/80

t = 5/8 hours

t = 0.625hours

t = 0.625 * 60 = 37.5minutes

Average speed required to complete the race in 1 hour = 100km/hr

Time used to complete first 50km = 0.625 hour

Time remaining: (1 - 0.625) hour = 0.375

Speed required = Distance left / time left

Speed required = 50 / 0.375

Speed required = 133.33km/hr

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Data:
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paperclips picked up first try: 10, 28, 30, 44
paperclips picked up second try: 16, 24, 32, 50
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