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Anarel [89]
2 years ago
6

Using the graph, predict how many paper clips a 7.5 V battery would pick up for both the 25-coil electromagnet and the 50-coil e

lectromagnet. Explain your reasoning for your prediction.
Physics
1 answer:
insens350 [35]2 years ago
8 0
Data:
25 turn electromagnet
batter voltage: 1.5 V , 3.0 V , 4.5 V, 6.0V
paper clips picked up first try: 5, 12, 14, 20
paper clips picked up second try: 7, 12, 17, 26
average: 6, 12, 15.5, 23

50 turn electromagnet
battery voltage: 1.5 V, 3.0 V, 4.5 V, 6.0 V
paperclips picked up first try: 10, 28, 30, 44
paperclips picked up second try: 16, 24, 32, 50
average: 13, 26, 31, 47
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Explanation:

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Pick a common happening , develop an explanation for it , and describe an experiment you could perform to test your explanation.
disa [49]
Plant's produce oxygen, to explain this you would state that the plant uses CO2 from the air and removes the carbon and then release breathable O2 into the atmosphere. To test this you could use a small fern and put it in a sealed container of some kind big enough to hold it, then add a burning candle in the container with the plant, since we know fire burms O2 and creates CO2 the plant should use the CO2 and create more O2 keeping the fire from burning out from lack of oxygen
5 0
3 years ago
How is amplitude changed in an instrument or tuning fork
azamat

Amplitude is affected by the energy wave in the instrument. High energy wave means high amplitude and low energy wave means low amplitude.

<u>Explanation:</u>

The amplitude of a periodic variable is a measure of its change over a single period. There are various definitions of amplitude, which are all functions of the magnitude of the differences between the variable's extreme values.

The amount of energy carried by a wave is related to the amplitude of the wave. Amplitude of an instrument is directly affected by the wave of the energy in the instruments. High energy wave means high amplitude and low energy wave means low amplitude in the instrument.

7 0
3 years ago
An uniform electric field of magnitude E = 100 N/C is oriented along the positive y-axis. What is the magnitude of the flux of t
Ede4ka [16]

Answer:

The magnitude of the flux of electric field through a square of surface area is zero.

Explanation:

E=100 NC^{-1}\\\\A=2 m^2\\\\Electic\,\,flux\,\,flux\,\,is\,\,given\,\,as:\\\\\phi_E=E.A\,cos\,\theta

It is given that square box is parallel to yz-plane which has normal vector perpendicular to plane in x-direction. Angle between normal vector of area and electric field is 90°. Substituting in (1)

\phi_E=E.A\,cos\,(90^o)\\\\\phi_E=0

4 0
3 years ago
In a charging process, 1 × 10^13 electrons are removed from one small metal sphere and placed on a second identical sphere. Init
liraira [26]

Answer:

r = 0.303m

= 30.3cm

Explanation:

Given that,

The number of electrons transferred from one sphere to the other,  

n  = 1 ×10 ¹³e le c t r o n s

The electrostatic potential energy between the spheres,  

U = − 0.061 J

The charge on an electron,  

q = − 1.6 × 10 ⁻¹⁹C

The coulomb constant,  

K = 8.98755 × 10 ⁹ N ⋅ m ² / C 2²

Due to the transfer of electrons, both spheres become equally and oppositely.

The charge gained by the sphere due to the excess of the electron is:  

q ₁ = n q

   = 1 ×10 ¹³ *  − 1.6 × 10 ⁻¹⁹

   = -1.6  × 10⁻⁶C

The charge left on the first sphere is =

q ₂ = -q₁ = 1.6  × 10⁻⁶C

The electric potential energy between two point charges is given by the following equation:

U = K q ₁q ₂/r

q ₁ and  q ₂ are the two charges.

r  is the distance between the charge and the point.

K  =  8.98755  ×  10 ⁹ N ⋅ m ² / C ²

we have:

-0.061 =  (8.98755  ×  10 ⁹ * (-1.6  × 10⁻⁶)²) / r

r = (18.41 ×  10 ⁻³) / 0.061

r = 0.303m

= 30.3cm

4 0
3 years ago
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