Since the new distance is 3 times the old distance,
the new force is (1/3²) = 1/9th of the old force.
That's kind-of Choice-D, but I really don't like the way choice-D is worded.
"9 times smaller" is really pretty meaningless.
There are two systems that contain only the fundamental frequency and they are the systems C and D.
<h3>What is fundamental frequency?</h3>
The term fundamental frequency refers to the lowest frequency of a vibrating body. It does not include the overtones or the harmonics.
From the image shown in the question, there are two systems that contain only the fundamental frequency and they are the systems C and D.
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The answer is B. A frame of reference that is accelerating.
After one day, the rate of increase in Delta Cephei's brightness is;0.46
We are informed that the function has been used to model the brightness of the star known as Delta Cephei at time t, where t is expressed in days;
B(t)=4.0+3.5 sin(2πt/5.4)
Simply said, in order to determine the rate of increase, we must determine the derivative of the function that provides
B'(t)=(2π/5.4)×0.35 cos(2πt/5.4)
Currently, at t = 1, we have;
B'(1)=(2π/5.4)×0.35 cos(2π*1/5.4)
Now that the angle in the bracket is expressed in radians, we can use a radians calculator to determine its cosine, giving us the following results:
B'(1)=(2π/5.4)×0.3961
B'(1)≈0.46
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Answer:
<h2>3.00m high</h2>
Explanation:
Gravitational potential energy of the diver is expressed mathematically as
P = mgh
m = mass of the diver (in kg)
g = acceleration due to gravity (in m/s²)
h = the height of the diver above the water surface.
Given m = 85.0kg, g = 9,8m/s² and P = 2.50x10³ Joules, wecan determine how high the diver is above the water surface bu substituting the given values into the formula;
h = P/mg
h = 2.50x10³/85*9.8
h = 2500/833
h ≈ 3.00m
The diver is 3.00m above the water surface.
