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Bess [88]
3 years ago
6

PLEASE HURRY AND HELP!!!!!!!!!

Physics
1 answer:
Mazyrski [523]3 years ago
7 0

Answer:

C

Explanation:

The SI unit of acceleration is the metre per second squared (m s−2); or "metre per second per second", as the velocity in metres per second changes by the acceleration value, every second.

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A 5.0 kg block is pushed 2.0 m at a con-
Alona [7]

Answer:

W_F=127.64283 J

Explanation:

Information Given:

m = 5kg  v=constant

Key: μ = Kinetic Friction (Kf)   θ = Theta α = 180° N = Normal Force

W_F=F_ydcosθ

W_F=Fdsinθ

_{net}F_y = sinθ-μN-mg=0

_{net}F_x = 0

N=Fcosθ

Fsinθ-μN=mg

Fsinθ-μFcosθ=mg

F=\frac{mgdsin(theta)}{sin(theta)-(Kf)cos(theta)} →W_F=\frac{mgdsin(theta)}{sin(theta)-(Kf)cos(theta)}

W_F=\frac{(2)(9.81)(2)sin(30)}{sin(30)-(0.40)cos(30)}

W_F=127.64283 J

3 0
3 years ago
What is the resultant force of the free body diagram?
GaryK [48]

1) Magnitude of the net force: 20.8 N

2) Angle: 35.2^{\circ} clockwise from positive x-direction

Explanation:

1)

First of all, we need to find the components of the resultant force along the horizontal and vertical direction.

We observe that there are two forces acting along the horizontal direction:

F_1=33 N\\F_2 = 16 N

We notice that they act in opposite directions, so the net force in the horizontal direction is the difference between these two forces:

F_x =F_1-F_2=33-16=17 N (to the right)

Instead, there is only one force acting in the vertical direction, so the net force in the vertical direction is:

F_y=F_3=12 N (downward)

Therefore, the magnitude of the net force can be found by using Pythagorean's theorem:

F=\sqrt{F_x^2+F_y^2}=\sqrt{17^2+12^2}=20.8 N

2)

Now we have to find the angle of the resultant net force. We can do it by using the following equation:

tan \theta = \frac{F_y}{F_x}

where

\theta is the angle, measured as clockwise from the positive x-direction (because the vertical net force is downward)

F_y = 12 N is the vertical net force

F_x=17 N is the horizontal net force

Solving, we find:

tan \theta=\frac{12}{17}=0.706

And so the angle is

\theta=tan^{-1}(0.706)=35.2^{\circ}

In a direction down with respect to the right.

Learn more about forces:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

About addition of vectors:

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

4 0
3 years ago
A stereo speaker produces a pure \"c\" tone, with a frequency of 262 hz. what is the period of the sound wave produced by the sp
jasenka [17]

Answer:

3.82 ms

Explanation:

The period of a wave is equal to the reciprocal of the frequency:

T=\frac{1}{f}

where f is the frequency.

In this problem, f = 262 Hz, so the period if this sound wave is

T=\frac{1}{262 Hz}=3.82\cdot 10^{-3} s=3.82ms

4 0
3 years ago
if the strength of the magnetic feild at a is 200 units and the strength of the magnetic field at b is 50 units what is the dist
IrinaVladis [17]

It would be 100 units.

7 0
3 years ago
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How can being physically fit help you emotionally
Svetlanka [38]
It can help you feel better about your self and body
7 0
4 years ago
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