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Veseljchak [2.6K]
3 years ago
15

Can someone help me please

Physics
2 answers:
Molodets [167]3 years ago
8 0
Meter would be the correct answer.
Evgen [1.6K]3 years ago
5 0
The last one: meter
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If a person believes that dreams have hidden meaning he or she would agree with Freud's ideas about _ content
uysha [10]
A.lucid because it makes more sense yo the answer how about you do it yourself
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3 years ago
A gry is an old English measure for length, defined as 1/10 of a line, where line is another old English measure for length, def
Valentin [98]

Answer:

0.2448 point²

Explanation:

1 gry = 1/10 line

1 line = 1/12 inch

=> 1 gry in inches = 1/10 * 1/12 = 1/120 inch

=> 1 inch = 120 gry

1 point = 1/72 inch

=> 1 inch = 72 points

Therefore,

120 gry = 72 points

=> 1 gry = 3/5 point

Therefore,

1 gry² = (3/5)² point²

1 gry² = 9/25 point²

This means that 0.68 gry² will be:

0.68 gry² = 0.68 * 9/25 point²

=> 0.68 gry² = 0.2448 point²

6 0
3 years ago
Why does the moon exert a greater tidal influence than the sun?
andreyandreev [35.5K]
Well, I'm not sure right now that it actually does.

But if it does, that's because the sun is about 400 times
FARTHER from the Earth than the moon is.
4 0
3 years ago
I need help! what are some sentences that help me explain Explain the process that creates wind?
Furkat [3]

Answer:

Explanation:

Wind is air in motion. It is produced by the uneven heating of the earth's surface by the sun. Since the earth's surface is made of various land and water formations, it absorbs the sun's radiation unevenly. Two factors are necessary to specify wind: speed and direction.

5 0
2 years ago
Read 2 more answers
The electron gun in a television tube is used to accelerate electrons with mass 9.109 × 10−31 kg from rest to 3 × 107 m/s within
zaharov [31]

Answer:

Electric field, E = 40608.75 N/C

Explanation:

It is given that,

Mass of electrons, m=9.1\times 10^{-31}\ kg

Initial speed of electron, u = 0

Final speed of electrons, v=3\times 10^7\ m/s

Distance traveled, s = 6.3 cm = 0.063 m

Firstly, we will find the acceleration of the electron using third equation of motion as :

a=\dfrac{v^2-u^2}{2s}

a=\dfrac{(3\times 10^7)^2}{2\times 0.063}

a=7.14\times 10^{15}\ m/s^2

Now we will find the electric field required in the tube as :

ma=qE

E=\dfrac{ma}{q}

E=\dfrac{9.1\times 10^{-31}\times 7.14\times 10^{15}}{1.6\times 10^{-19}}

E = 40608.75 N/C

So, the electric field required in the tube is 40608.75 N/C. Hence, this is the required solution.

3 0
3 years ago
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