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lesya [120]
3 years ago
15

In December, why does the sun have a much lower azimuth?

Physics
1 answer:
patriot [66]3 years ago
5 0

Answer:

The earth is tilted away from the sun more, and the angular perspective someone has on it is lower, which contributes to the cooler temperatures.

(stg there is no plagiarism, you can search it up)

Explanation:

BRAINLIEST PLZ

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Define bond length using your own words​
Brut [27]

Answer:

the free encyclopedia. In molecular geometry, bond length or bond distance is defined as the average distance between nuclei of two bonded atoms in a molecule. It is a transferable property of a bond between atoms of fixed types, relatively independent of the rest of the molecule.

Explanation:

6 0
3 years ago
Watt-hours is a measure of energy, just like kilowatt-hours. How can you convert this to Joules?
satela [25.4K]

Work with your units:

1 watt-hour = 1 (joule/second) · (hour) = 1 (joule-hour / second)

(1 joule-hour/sec) · (3600 sec/hour) = 3600 joules

So 1 watt-hour = 3,600 joules

3 0
3 years ago
If you were to travel from the equator to the higher latitudes (near either pole) on Saturn, the differential rotation would cau
Dmitrij [34]

Answer:

Saturn's differential rotation will cause the length of a day measures to be longer by 0.4 hours

Explanation:

Differential rotation occurs due to the difference in angular velocities of an object as we move along the latitude of the or as we move into different depth of the object, indicating the observed object is in a fluid form

Saturn made almost completely of gas and has differential motion given as follows

Rotation at the equator = 10 hours 14 minutes

Rotation at high altitude = 10 hours 38 minutes

Therefore;

The differential rotation = 10 hours 38 minutes - 10 hours 14 minutes

The differential rotation = 24 minutes = 24 minutes × 1 hour/(60 minutes) = 0.4 hours

The differential rotation = 0.4 hours

Therefore, the measured day at the higher altitude will be 0.4 longer than at the equator.

8 0
3 years ago
You have a grindstone (a disk) that is 95.2 kg, has a 0.399 m radius, and is turning at 93 rpm, and you press a steel axe agains
olya-2409 [2.1K]

Answer:

angular acceleration is -0.2063  rad/s²

Explanation:

Given data

mass m = 95.2 kg

radius r = 0.399 m

turning ω = 93 rpm

radial force N  = 19.6 N

kinetic coefficient of friction  μ = 0.2

to find out

angular acceleration

solution

we know frictional force that is = radial force × kinetic coefficient of friction

frictional force = 19.6 × 0.2

frictional force = 3.92 N

and

we know moment of inertia  that is

γ =  I ×α = frictional force × r

so

γ  = 1/2 mr²α

α  = -2f /mr

α  = -2(3.92) /95.2 (0.399)

α  = - 7.84 / 37.9848 = -0.2063

so angular acceleration is -0.2063  rad/s²

3 0
3 years ago
Which tool would you use to measure how long it takes a toy car to go down a ramp?
Ratling [72]
The answer will be C, a stopwatch :)
4 0
3 years ago
Read 2 more answers
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