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4 years ago

In December, why does the sun have a much lower azimuth?

Physics

1 answer:

patriot [66]4 years ago

5 0

Answer:

The earth is tilted away from the sun more, and the angular perspective someone has on it is lower, which contributes to the cooler temperatures.

(stg there is no plagiarism, you can search it up)

Explanation:

BRAINLIEST PLZ

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The axoplasm of an axon has a resistance Rax. The axon's membrane has both a resistance (Rmem) and a capacitance (Cmem). A singl

dybincka [34]

Answer:

The expression is Vmem = ΔV - I*Rax

Explanation:

According to the picture, if switch S is closed, the Cmem will be short. If Vcap = 0, the current flows through the capacitor only (not through Rmem), thus Vmem = 0 after closing S.

When C is fully charged, then we have:

Vmem = ΔV - I*Rax

8 0

4 years ago

At time t=0 , in your frame of reference Z, you measure the back of the spaceship to be at x=0 and the front of the ship to be a

Liula [17]

An equation relating the length that you measure l to the ship's proper length l0 is

l =l0/y. This is further explained below.

<h3>What is an equation relating the length that you measure l to the ship's proper length l0?</h3>

Generally, Any object's length in a moving frame will look shortened or contracted when seen in that direction. The Lorentz transformation may be used to determine the amount of contraction.

In conclusion, To use the Lorentz Lorentz transformation, the length Lo-x2 - may be determined if it is measured in the moving reference frame. Hence the Resultant l = l0/y.

Read more about Lorentz transformation

brainly.com/question/16284701

#SPJ1

7 0

3 years ago

Find the components to write this vector in unit vector notation: 63.5 A please help

IrinaVladis [17]

Vector is perpendicular to x axis or i component.

Hence i component is 0

j component is 63.5

$\\ \sf\longmapsto \overrightharpoon{A}=0\hat{i} +63.5\hat{j}$

6 0

3 years ago

Bro why cant I post this T-T

Leni [432]

Answer: 12.0 m/s^2

Explanation:

Let $\alpha$ be the angular acceleration of the end of the rod

Taking torque about the link, we have:

$\tau = W \times OM\\ or\\ \tau = mg\times \left(\dfrac{L}{2}\right)\sin 55^\circ ....(i)$

Torque is also given in terms of moment of inertia of the rod and its angular acceleration i.e.

$\tau = I_{rod}\ \alpha......(ii)$

From equations (i) and (ii) we have:

$mg\times \left(\frac{L}{2}\right)\sin 55^\circ = \left(\frac{mL^2}{3}\right)\alpha\ \ \ \ \ \ \ (\because I_{rod} = \dfrac{mL^2}{3}) \\ \\ \alpha = \left(\frac{3g}{2L}\right)\sin 55^\circ\\ \\ \alpha = \left(\frac{3\times 9.8}{2\times 2.4}\right)\sin 55^\circ\\ \\ \boxed{\alpha = 5.02\ rad/s^2} }$

The acceleration of the end of the rod farthest from the link is given by:

$a = L\alpha\\ \\ a = (2.4\ m)(5.02\ rad/s^2)\\ \\ \boxed{a = 12.0\ m/s^2}$

7 0

2 years ago

Under what atmospheric condition is fog most often formed in the san joaquin valley?

GalinKa [24]

It seems that you have missed the necessary options for us to answer this question so I had to look for it. Anyway,here is the answer. The atmospheric condition in which <span>fog is most often formed in the san Joaquin valley is stable stability. Hope this helps.</span>

4 0

4 years ago