So E = 2x10^-3W/m^2*(π*(3.0x10^-3m)^2)*1min*60s... = 3.4x10^-6J
(1) Doubling of the current through the wire will result in doubling of its magnetic field.
The magnetic field around a wire is a function of the current I and radial distance r

(with mu denoting the magnetic permeability of the medium). So, B is directly proportional to I. The field magnitude will double with the doubled current from 5A to 10A
(2) Using the same formula as in (1), we can see that the magnetic field is inversely proportional to the radial distance from the wire. So, a particle at 20cm will experience half the magnitude compared to a particle at 10cm.
(3) Answer
If a particle with a charge q moves through a magnetic field B with velocity v, it will be acted on by the magnetic force

So, a particle with charge -2uC will experience a magnetic force of same magnitude but opposite direction (and perpendicular to B) as compared to a particle with a charge of 2uC
The resistance of the conductor is 0.07940 Ohms.
<h3>What is the relation between resistance and area of wire?</h3>
The wire's resistance is inversely related to its cross-sectional area; as the area drops, so does the resistance.
and it is formulated as:

where,
<em>p </em>- resistivity of the conductor (0.0214-ohm mm²/m)
R - resistance
l- length of conductor (50 feet) (15.24 m)
s - the area of the wire
Thus the resistance can be calculated as
R = 0.07940 Ohms.
Learn more about resistance here:
brainly.com/question/11431009
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