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lawyer [7]
2 years ago
13

A 40kg cart gains a KE of 200J. How fast does it go?

Physics
1 answer:
34kurt2 years ago
7 0

Answer:

3.16 m/s

Explanation:

Use the formula

k =  \frac{m {v}^{2} }{2}  \\ v =  \sqrt{ \frac{2k}{m} }  \\ v =  \sqrt{ \frac{2(200)}{40} }  \\ v = 3.16 \frac{m}{s}

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Choose all facts that increase the orbital velocity of a vessel around planet B. Bigger mass of planet B smaller mass of planet
telo118 [61]

Answer:

- Bigger mass of planet B  

- orbiting closer to planet B

Explanation:

The orbital velocity of the vessel around the planet can be found by equalizing the force of gravity between the vessel and the planet and the centripetal force:

G\frac{mM}{r^2}=m\frac{v^2}{r}

where

G is the gravitational constant

m is the mass of the vessel

M is the mass of the planet

r is the distance between the vessel and the centre of the planet

v is the orbital velocity of the vessel

Re-arranging the formula, we find an expression for v:

v=\sqrt{\frac{GM}{r}}

We see that:

- the bigger the mass of the planet, M, the bigger the velocity

- the bigger the distance between the vessel and the planet, r, the smaller the velocity

So, the correct choices that increase the orbital velocity are:

- Bigger mass of planet B  

- orbiting closer to planet B

6 0
4 years ago
according to newtons first law of motion, what will an object in motion do when no external force acts on it?​
shutvik [7]

Answer:

The object will not move.

Explanation:

If nothing pushes against it it will not move. If its not on a slant it will not move.

4 0
3 years ago
Read 2 more answers
Consider a father pushing a child on a playground merry-go-round. The system has a moment of inertia of 84.4 kg.m^2. The father
Sophie [7]

Answer:

Explanation:

Given that:

the initial angular velocity \omega_o = 0

angular acceleration \alpha = 4.44 rad/s²

Using the formula:

\omega = \omega_o+ \alpha t

Making t the subject of the formula:

t= \dfrac{\omega- \omega_o}{ \alpha }

where;

\omega = 1.53 \ rad/s^2

∴

t= \dfrac{1.53-0}{4.44 }

t = 0.345 s

b)

Using the formula:

\omega ^2 = \omega _o^2 + 2 \alpha \theta

here;

\theta = angular displacement

∴

\theta = \dfrac{\omega^2 - \omega_o^2}{2 \alpha }

\theta = \dfrac{(1.53)^2 -0^2}{2 (4.44) }

\theta =0.264 \ rad

Recall that:

2π rad = 1 revolution

Then;

0.264 rad = (x) revolution

x = \dfrac{0.264 \times 1}{2 \pi}

x = 0.042 revolutions

c)

Here; force = 270 N

radius = 1.20 m

The torque = F * r

\tau = 270 \times 1.20 \\ \\  \tau = 324 \ Nm

However;

From the moment of inertia;

Torque( \tau) = I \alpha \\ \\  Since( I \alpha) = 324 \ Nm. \\ \\  Then; \\ \\  \alpha= \dfrac{324}{I}

given that;

I = 84.4 kg.m²

\alpha= \dfrac{324}{84.4} \\ \\  \alpha=3.84 \ rad/s^2

For re-tardation; \alpha=-3.84 \ rad/s^2

Using the equation

t= \dfrac{\omega- \omega_o}{ \alpha }

t= \dfrac{0-1.53}{ -3.84 }

t= \dfrac{1.53}{ 3.84 }

t = 0.398s

The required time it takes= 0.398s

5 0
3 years ago
A laser source has a bandwidth of 30GHz (a) Calculate the coherence length of the source b) What is the time separation of secti
abruzzese [7]

Explanation:

It is given that,

Bandwidth of a laser source, f=30\ GHz=30\times 10^9\ Hz

(b) Let t is the time separation of sections of sections of the light wave that can still interfere. The time period is given by :

T=\dfrac{1}{f}

T=\dfrac{1}{30\times 10^9}

T=3.33\times 10^{-11}\ s

(a) Let h is the coherence length of the source. It is given by :

l=c\times T

c is the speed of light

l=3\times 10^8\times 3.33\times 10^{-11}

l = 0.0099 m

Hence, this is the required solution.

6 0
3 years ago
Hi i need answers for this. Thank you!! this is also really important and is due tomorrow at 9am!!
Allushta [10]

Answer:

You're four sentences should include about how the roller coaster has the most potential energy at the top of the track, and the opposing energy, "kinetic" has the most kinetic energy when going down the hill.

Explanation:

Kinetic - In-Motion.

Potential - Gathering Energy to go into Motion.

( I'll try to answer questions to clear up confusion. )

7 0
3 years ago
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