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3 years ago

26. A transformer increases or decreases

Physics

1 answer:

uysha [10]3 years ago

7 0

Answer:

Explanation:

Single-phase transformers can operate to either increasing or decreasing the voltage applied to the primary winding. When a transformer is used to “increase” the voltage on the secondary winding with respect to the primary, it is called a Step-up transformer

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A force of 12 N changes the momentum of a toy car from 3kgm/s t0 10kgm/s. Calculate the time the force took to produce this chan

yan [13]

Answer:

Time = 0.58 seconds

Explanation:

Given the following data;

Initial momentum = 3 kgm/s

Final momentum = 10 kgm/s

Force = 12 N

To find the time required for the change in momentum;

First of all, we would determine the change in momentum.

$Change \; in \; momentum = final \; momentum - initial \; momentum$

$Change \; in \; momentum = 10 - 3$

Change in momentum = 7 kgm/s

Now, we can find the time required;

Note: the impulse of an object is equal to the change in momentum experienced by the object.

Mathematically, impulse (change in momentum) is given by the formula;

$Impulse = force * time$

Making "time" the subject of formula, we have;

$Time = \frac {impulse}{force}$

Substituting into the formula, we have;

$Time = \frac {7}{12}$

Time = 0.58 seconds

6 0

3 years ago

When a dielectric slab is inserted between the plates of one of the two identical capacitors

tatiyna

Answer:(A-P,S;B-P,S;C-Q,S;D-P,S)

Solution

(A)→P,S,(B)→P,S,(C)→Q,S,(D)→P,S.

Explanation:

4 0

2 years ago

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An astronomer would most likely use the doppler effect to question 12 options: 1) measure the color of a star. 2) measure the pa

zalisa [80]

The answer would be number four. I'm sorry if I am too late. Byes.....

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3 years ago

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Find the ratio of the new/old periods of a pendulum if the pendulum were transported from earth to the moon, where the accelerat

vichka [17]

The period of a pendulum is given by
$T=2 \pi \sqrt{ \frac{L}{g} }$
where L is the pendulum length and g is the gravitational acceleration.

We can write down the ratio between the period of the pendulum on the Moon and on Earth by using this formula, and we find:
$\frac{T_m}{T_e} = \frac{2 \pi \sqrt{ \frac{L}{g_m} } }{2 \pi \sqrt{ \frac{L}{g_e} } }= \sqrt{ \frac{g_e}{g_m} }$
where the labels m and e refer to "Moon" and "Earth".

Since the gravitational acceleration on Earth is $g_e = 9.81 m/s^2$ while on the Moon is $g_m=1.63 m/s^2$ , the ratio between the period on the Moon and on Earth is
$\frac{T_m}{T_e}= \sqrt{ \frac{g_e}{g_m} }= \sqrt{ \frac{9.81 m/s^2}{1.63 m/s^2} }=2.45$

3 0

3 years ago

A miner of mass 90kg travels down a slide calculate the potential energy of the miner when he moves15m vertically downwards

Lena [83]

Answer:

Gravitational Potential Energy = mgh

Explanation:

As the miner moves down, the GPE changes because the height changes.

Gravitational Potential Energy = mgh

8 0

3 years ago