A) 8.11 m/s
For a satellite orbiting around an asteroid, the centripetal force is provided by the gravitational attraction between the satellite and the asteroid:
where
m is the satellite's mass
v is the speed
R is the radius of the asteroide
h is the altitude of the satellite
G is the gravitational constant
M is the mass of the asteroid
Solving the equation for v, we find
where:
Substituting into the formula,
B) 11.47 m/s
The escape speed of an object from the surface of a planet/asteroid is given by
where:
Substituting into the formula, we find:
Answer:
The acceleration that earth experiences due to gravitational pull is = 9.81 
.
Explanation:
The acceleration that earth experiences due to gravitational pull is called the acceleration due to gravity. its value is 9.81 and its unit is .
When the object move upwards than in that case the earth gravitational force pulls down the body.
The formula of force due to gravity on the body is given as
F = mg
where g = acceleration due to gravity.
Due to this acceleration the body falls upon the surface of the earth.
The velocity of the second glider after the collision is 4.33 m/s rightward.
<h3>
Velocity of the second glider after the collision</h3>
Apply the principle of conservation of linear momentum;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
- m₁ is mass of first glider
- m₂ is mass of second glider
- u₁ is initial velocity of first glider
- u₂ is initial velocity of second glider
- v is the final velocity of the gliders
(2)(1) + (3)(5) = (2)(2) + 3v₂
17 = 4 + 3v₂
3v₂ = 17 - 4
3v₂ = 13
v₂ = 13/3
v₂ = 4.33 m/s
Thus, the velocity of the second glider after the collision is 4.33 m/s rightward.
Learn more about linear momentum here: brainly.com/question/7538238
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Answer:
t = 4.28 s
Explanation:
The horizontal speed of a marble = 7 m/s
The horizontal displacement covered by the marble = 30 m
We need to find the time for which the marble is in air. Let the time is t. Using the formula for speed to find it as follows :
So, it will in the air for 4.28 s.
