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sweet [91]
2 years ago
11

If the coefficient of kinetic friction between tires and dry pavement is 0.98, what is the shortest distance in which you can st

op an automobile by locking the brakes when traveling at 34.7 m/s
Physics
1 answer:
Ilia_Sergeevich [38]2 years ago
7 0

Answer:

The shortest distance is 62.7 m

Explanation:

Given;

coefficient of kinetic friction, μk = 0.98

initial velocity, u = 34.7 m/s

Frictional force on the tire;

Fk = -μkN

where;

N is normal reaction = mg

ma = -μkN

ma = -μkmg

a = -μkg

a = - 0.98 x 9.8 = -9.604 m/s²

The shortest distance in which you can stop an automobile by locking the brakes:

Apply equation of motion;

v² = u² + 2ax

where;

v is the final velocity

u is the initial velocity

a is the acceleration of the  automobile

0 = 34.7² + 2(-9.604)x

0 = 1204.09 - 19.208x

19.208x = 1204.09

x = 1204.09/19.208

x = 62.7 m

Therefore, the shortest distance in which you can stop an automobile by locking the brakes when traveling at 34.7 m/s is 62.7 m

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Two blocks are connected as shown in the diagram below. Assume that the ramp is frictionless. Draw the force diagram for the blo
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(see image for further explanation)

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Which major planet has the largest . . . A. semimajor axis? B. average orbital speed around the Sun? C. orbital period around th
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<h2>Mercury, Neptune, and Jupiter </h2>

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5. A person fishing from a pier observes that four wave crests pass by in 7.0 s and estimates that the distance between two succ
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Answer:

v= 1.71 m/s

Explanation:

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Distance between two successive crests = 4.0 m

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