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Slav-nsk [51]
3 years ago
8

What influences the strength of an electric field?

Physics
1 answer:
Anastasy [175]3 years ago
3 0
The source/size of the charge.

The distance from the source of charge
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An electric toaster is rated 1200 watts at 120 volts. what is the total electrical energy used to operate the toaster for 30 sec
Anarel [89]
Energy is calculated as power*time, so give the wattage of 1200 W (equivalent to 1200 Joules/second) and time of 30 seconds, multiplying these gives 36000 J or 36 kJ of electrical energy.

If electrical charge or current is needed: Power = voltage * current, so given the power of 1200 watts and voltage of 120 V, current is 1200 W / 120 V = 10 Amperes. Charge is calculated by multiplying 10 A*30 s = 300 C.
3 0
3 years ago
A textbook of mass 2.05 kg rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose d
blsea [12.9K]

Answer:

a. 7.38 N b. 40.87 N c. 0.113 kg-m²

Explanation:

a. Let T be the tension in the cord. For the textbook, T = ma since no other force acts on it and it is an horizontal force, and m = mass = 2.05 kg and a = acceleration. We find the acceleration from s = ut + 1/2at² where u = initial speed = 0 (since it starts from rest),  s = distance moved = 1.30 m and t = time = 0.850 s.

Substituting these values into s,

1.30 m = 0 × 0.850 + 1/2a × 0.850² = 0 + 0.36125a

1.30 = 0.36125a

a = 1.30/0.36125 = 3.6 m/s²

Substituting this into T, we have

T = ma = 2.05 kg × 3.6 m/s² = 7.38 N

b.  Let T be the tension in the cord attached to the book. The book has the only vertical forces acting on it as the tension, T(acting upwards) and its weight mg (acting downwards). So the net force acting on it is

T - mg = ma

T = m(a + g)

substituting a = 3.6 m/s² and g = 9.8 m/s² and m = 3.05 kg

T = 3.05(3.6 + 9.8) = 3.05 × 13.4 = 40.87 N

c. Since the tangential acceleration of the pulley is also the acceleration of the masses, the a = rα where r = radius of pulley = 0.200 m/2 = 0.100 m and α = angular acceleration of the pulley.

α = a/r = 3.6 m/s² ÷ 0.100 m = 36 rad/s²

Now, the torque on the pulley τ = Tr = Iα where I = moment of inertia of pulley about its rotational axis and T = tension in cord attached to book and r = radius of pulley = 0.200 m/2 = 0.100 m

From the equation above, I = Tr/α

Substituting the variables we have

I = 40.87 N × 0.100 m ÷ 36 rad/s² = 0.113 kg-m²

4 0
3 years ago
Read 2 more answers
Engineers are starting on a new project to develop technology. Which of these
Ilya [14]
The answer should be C. In this question
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3 years ago
A 50 kg bear climbed on the tree branch 10 meters above the ground. If the bear descends to 5 meters above the ground, its poten
Simora [160]
<h3>Option A. 4900 J or joules</h3>
6 0
3 years ago
An average man is 80 k (800 N) and the area of the shoes he is wearing is 0.0092 m2. What is the pressure he is exerting on the
S_A_V [24]

Answer:

P = 86956.52 Pa

Explanation:

Data:

  • F = 800 N
  • A = 0.0092 m²
  • P = ?

Use the formula:

  • \boxed{\bold{P=\frac{F}{A}}}

Replace and solve:

  • \boxed{\bold{P=\frac{800\ N}{0.0092\ m^{2}}}}
  • \boxed{\bold{P=86956.52\ Pa}}}

The pressure it exerts on the ground is <u>86956.52 Pascal.</u>

Greetings.

7 0
2 years ago
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