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Slav-nsk [51]
3 years ago
8

What influences the strength of an electric field?

Physics
1 answer:
Anastasy [175]3 years ago
3 0
The source/size of the charge.

The distance from the source of charge
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A thick steel sheet of area 100 in.2 is exposed to air near the ocean. After a one-year period it was found to experience a weig
vladimir1956 [14]

Answer:

Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.

Explanation:

The corrosion rate is the rate of material remove.The formula for calculating CPR or corrosion penetration rate is

CPR=\frac{KW}{DAT}

K= constant depends on the system of units used.

W= weight =485 g

D= density =7.9 g/cm³

A = exposed specimen area =100 in² =6.452 cm²

K=534 to give CPR in mpy

K=87.6  to give CPR in mm/yr

mpy

CPR=\frac{KW}{DAT}

        =\frac{534\times( 485g)\times( 10^3mg/g)}{(7.9g/cm^3) \times (100in^2)\times (24h/day)\times (365day/yr)\times 1yr}

        =37.4mpy

mm/yr

CPR=\frac{KW}{DAT}

        =\frac{87.6\times (485g)\times (10^3 mg/g)}{(7.9g/cm^3)\times (100in^2)\times(2.54cm/in)^2\times (24h/day)\times (365day/yr)\times 1yr}

       =0.952 mm/yr

Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.

3 0
4 years ago
Weight is measured in: grams, kilograms, metric tons, or pounds
sergejj [24]
'Gram', 'kilogram', and 'metric ton' are units of mass, not weight.

'Pound' can be either a unit of mass or of force.  Most people
use it most of the time to mean weight.
8 0
3 years ago
A chunk of metal has a volume of
Alla [95]

Answer:

7213.7kg/m³

Explanation:

Given parameters:

Volume of the metal chunk  = 0.131m³

Mass of the metal chunk  = 945kg

Unknown:

Density of the metal chunk  = ?

Solution :

To solve this problem, density is the mass per unit volume. It is mathematically expressed as;

  Density  = \frac{mass}{volume}  

 So;

 Density  = \frac{945}{0.131}   = 7213.7kg/m³

5 0
3 years ago
Can someone help<br> please and thank you:)
Dmitriy789 [7]

Answer:

its the ultraviolet lights

6 0
3 years ago
A motorcyclist sees a branch in the road and hits the brakes, slowing down at -6.42 m/s. if it takes him 2.85 seconds to stop, w
TEA [102]

Use the definition of average acceleration:

<em>a</em> = ∆<em>v</em> / <em>t</em>

If <em>v</em> is the starting speed, then ∆<em>v</em> = 0 - <em>v</em>, so solve for <em>v</em> :

-6.42 m/s² = (0 - <em>v</em>) / (2.85 s)

<em>v</em> = (6.42 m/s²) (2.85 s)

<em>v</em> ≈ 18.3 m/s

5 0
3 years ago
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