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vovikov84 [41]
3 years ago
8

What is combustion and how does it affect the carbon cycle?

Chemistry
1 answer:
kumpel [21]3 years ago
3 0
Combustion is burning and that usually produces carbon in the reaction adding it to the atmosphere
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a 32 gram radioactive sample has a half-life of 2 days how much of the original sample remains after 6 days
DiKsa [7]
<span>After 6 days, only 4 grams of the original amount will remain after 6 days. I have attached an image on how to calculate half-life so you can plug your give value into the formula.

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To add, </span>half-life means for<span> a substance decaying exponentially, the amount of time it takes for the amount of the substance to diminish by </span>half.

4 0
3 years ago
the elements helium (he), neon (ne), and xenon (xe) are all part of the same on the periodic table plz answer correctly gets a b
bagirrra123 [75]
Noble gas. Noble gas, any of the seven chemical elements<span> that make up Group 18 (VIIIa) of the </span>periodic table<span>. The </span>elements<span> are </span>helium<span> (</span>He<span>), </span>neon<span> (</span>Ne<span>), argon (Ar), krypton (Kr), </span>xenon<span> (</span>Xe<span>), radon (Rn), and oganesson (Og)</span>
3 0
3 years ago
Read 2 more answers
an ideal otto cycle with argon as the working fluid has a compression ratio of 8. the minimum and maximum temperatures in the cy
Verizon [17]

The specific heat of gases can be taken roughly as a constant for differences in the order of 100⁰ C from ambient. Variation is crucial and cannot be disregarded for temperatures of more than, let's say 500 ⁰C or 1000⁰C.

  1. The ideal gas constant is the difference between cp and cv for low pressures (the ideal gas).
  2. The classical statistical physics principles for ideal non-interacting gases are found in any university physics primer.
  3. The demonstration that pV/T = constant is typically included in texts on macroscopic thermodynamics suggests that while temperature changes depend on specific heats, the opposite is also true.
  4. Real gas behavior requires a more complex explanation.
  5. As a result, we employ two techniques to determine the specific heat of gases: at constant volume and constant pressure.
  6. The value of the heat capacity at constant pressure is always greater than the value of the heat capacity at constant volume because the former also takes into account the value of the heat energy required to expand the substance against the constant pressure as its temperature rises.

To learn about Real gas

<u>brainly.com/question/17355868</u>

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8 0
1 year ago
How many grams of magnesium (Mg, 24.30 g/mol) are in 7.43x10^22 atoms of Mg?
jeyben [28]

Given the number of Mg atoms is 7.43 * 10^{22} atoms

We know that 1 mol of any substance has Avogadro number (6.022 * 10^{23}) of formula units.

Converting number of atoms to mol:

7.43 * 10^{22} atoms * \frac{1 mol}{6.022*10^{23} atoms}   = 0.123 mol Mg

Converting mol to mass of Mg:

0.123 mol * \frac{24.30 g}{1 mol} = 2.99 g Mg

Therefore mass of Mg is <u>2.99 g</u>

3 0
4 years ago
1. What volume of gas (NU) is formed by the interaction of 13 g of zinc with 400 g of sulfuric acid solution with a mass fractio
Svetllana [295]

Answer:

4.5L of gas are produced

Explanation:

Based on the reaction:

Zn + H2SO4 → ZnSO4 + H2(g)

<em>Where 1 mole of Zn reacts with 1 mole of sulfuric acid to produce 1 mole of H2, the gas</em>

<em />

To solve this question we must find the moles of each reactant in order to find limiting reactant and, thus, the moles of H2 produced. Then using PV=nRT we can find the volume of the gas:

<em>Moles Zn -Molar mass: 65.38g/mol-</em>

13g * (1mol / 65.38g) = 0.20 moles Zn

<em>Moles H2SO4 -Molar mass: 98g/mol-</em>

400g * 10% = 40g H2SO4 * (1mol / 98g) = 0.41 moles H2SO4

As the ratio of the reaction is 1:1, the limiting reactant is Zn and the moles produced of H2 are 0.20 moles

Using PV = nRT; V = nRT/ P

<em>Where V is the volume of the gas </em>

<em>n are the moles = 0.20 moles</em>

<em>R is gas constant = 0.082atmL/molK</em>

<em>T is absolute temperature = 273.15K at STP</em>

<em>P is pressure = 1atm at STP</em>

<em />

V = 0.20mol*0.082atmL/molK*273.15K / 1atm

V = 4.5L of gas are produced

<em />

5 0
3 years ago
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