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lesantik [10]
3 years ago
9

What is the meaning of critical angle in physics​

Physics
1 answer:
bonufazy [111]3 years ago
6 0

Answer:

It's an Angle of incidence that provides a 90° angle but is also refracted at the same time. it's used to find the water-air boundary (which is 48.6 degrees). in addition, its an angle of incidence value.

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What is one of the drawbacks to the use of solar energy for generating electricity?
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Solar energy is one of the renewable energy sources that is invested around the world because of its large potential. the sun as a free source can sometimes bring a drawback. one of the drawbacks is that it cannot be harnessed when storms or rains are present in the weather. it is also expensive and young.
7 0
3 years ago
a projectile leaves the ground with a velocity of 35 meters per second at an angle 32° what is the maximum height
Nina [5.8K]
To determine the maximum height for the projectile, we can use the timeless kinematics equation V _{f} ^{2} -V_{i}^{2}=2a \Delta y and plug in what we know. For V _{f} ^{2}, we know it is zero because at the highest location of flight, there is no vertical velocity. For V _{i} ^{2}, we know it is (35sin(32))^{2} since the vertical component is the sine of the velocity. We need to solve for y, so it is left as-is. Since the only acceleration is g, we can substitute -9.81 into it. Solving for the equation yields a solution of 17.55 m for \Delta y.
6 0
4 years ago
What are the characteristics of globular cluster stars?
AlekseyPX
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3 0
3 years ago
An unsuspecting bird is coasting along in an easterly direction at 1.00 mph1.00 mph when a strong wind from the south imparts a
grin007 [14]

Answer:

2.375 m, 54°

Explanation:

I will be doing this applying the vector format of i and j. I hope that's not confusing for you. Where, i = East and j = North.

First, we convert the velocity from miles per hour to meters per second. Remember that 1 mile = 1609 meters

u = 1 mph East = 1.00i + 0j mph

u = (1.00i + 0j) mph * (1609 m / 1 mile) * ( 1 hr / 3600 s) = 0.45i + 0j m/s

a = 0.4 m/s² FROM THE SOUTH

a = 0.4 m/s² North = 0i + 0.4j m/s²

Next, we proceed to use the equation of motion to solve

sf = si + ut + 1/2at²

Let's assume that si = 0, this means that

sf = ut + 1/2at², now we substitute for u, t and a to get

sf = (0.45i + 0j m/s) * 3.1 s + 1/2 * (0i + 0.4j m/s²) * (3.1s)²

sf = (1.395i + 0j m) + (0+1.922j m)

sf = 1.395i + 1.922j m

This means that after 3.1 s, the birds displacement from the start is 1.395 m in the East direction and 1.922 m in the North direction.

Finding the resultant now will be

|sf| = √(1.395² + 1.922²) m

|sf| = √(1.946 + 3.694) m

|sf| = √5.64

|sf| = 2.375 m

direction = Tanθ = (j/i)

θ = Tan^-1 (j/i)

θ = Tan^-1(1.922/1.395)

θ = Tan^-1(1.378)

θ = 54° North East

4 0
3 years ago
As you zip through space in your PPS (personal propulsion suit), your pulse rate as you count it is 109 bpm 109 bpm (beats per m
Mrrafil [7]

Answer:

The speed is 2.427 x10⁸ m/s

Explanation:

The equation for measured time is the following:

t'=xt_{o}

Where

x = 0.587

Replacing:

t'=0.587t_{o}

The equation for the speed is:

t'=\frac{t_{o} }{\sqrt{1-(\frac{v^{2} }{c^{2} }) } } \\0.587t_{o} =\frac{t_{o}  }{\sqrt{1-(\frac{v^{2} }{c^{2} }) } }\\0.587=\sqrt{1-\frac{v^{2} }{c^{2} } } \\0.587^{2} =1-\frac{v^{2} }{c^{2} }

Rearrange the expression:

0.344=1-\frac{x^{2} }{c^{2} } \\v=\sqrt{0.656c^{2} } =0.809c

Where c = 3x10⁸m/s

Replacing:

v = 0.809 * 3x10⁸ = 2.427 x10⁸ m/s

8 0
4 years ago
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