A 54-kg ice skater pushes off the wall of the rink, giving herself an initial speed of 3.5 m/s . She then coasts with no further
1 answer:
Answer:
Displacement is 72.917 m .
Explanation:
Given :
Mass of cyclist , m = 54 kg .
Initial speed , u = 3.5 m/s .
Frictional coefficient between skates and ice is , .
We need to find its the displacement produced by it .
Frictional Force ,
Therefore, its acceleration ,
We know , by equation of motion .
Hence , this is the required solution .
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Answer:
d = 52 μm
Explanation:
given,
wavelength of the light source (λ)= 550 nm
distance to form interference pattern(D) = 1.5 m
y = 1.6 cm = 0.016 m
width of the slits = ?
now, using displacement formula
for the first maxima, m = 1
d = 5.2 x 10⁻⁶ m
d = 52 μm
hence, the width of her slits is equal to d = 52 μm
Answer:
15.8 V
Explanation:
The relationship between capacitance and potential difference across a capacitor is:
where
q is the charge stored on the capacitor
C is the capacitance
V is the potential difference
Here we call C and V the initial capacitance and potential difference across the capacitor, so that the initial charge stored is q.
Later, a dielectric material is inserted between the two plates, so the capacitance changes according to
where k is the dielectric constant of the material. As a result, the potential difference will change (V'). Since the charge stored by the capacitor remains constant,
So we can combine the two equations:
and since we have
V = 71.0 V
k = 4.50
We find the new potential difference: