1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
koban [17]
3 years ago
7

A 54-kg ice skater pushes off the wall of the rink, giving herself an initial speed of 3.5 m/s . She then coasts with no further

effort. The frictional coefficient between skates and ice is 0.024. How far does she go?
Physics
1 answer:
EastWind [94]3 years ago
3 0

Answer:

Displacement is 72.917 m .

Explanation:

Given :

Mass of cyclist , m = 54 kg .

Initial speed , u = 3.5 m/s .

Frictional coefficient between skates and ice is , \mu= 0.024 .

We need to find its the displacement produced by it .

Frictional Force , F=\mu (mg)=0.024\times 54\times 3.5=4.536\ N.

Therefore, its acceleration , a=\dfrac{F}{m}=\dfrac{4.536}{54}=0.084\ .

We know , by equation of motion .

v^2-u^2=2\times a \times s\\\\s=\dfrac{v^2-u^2}{2\times a}=\dfrac{0-3.5^2}{2 \times (-0.084)}=72.917\ m.

Hence , this is the required solution .

You might be interested in
What are the charges of the subatomic particles?
kotegsom [21]
A particle smaller than an atom or a <span>cluster of such particles </span>
3 0
3 years ago
Suppose that the space shuttle Columbia accelerates at 14.0 m/s2 for 8.50 minutes after takeoff.
givi [52]

Answer:

A. speed = 7.14 Km/s

B. distance = 1820.7 Km

Explanation:

Given that: a = 14.0 m/s^{2}, t = 8.50 minutes.

But,

t = 8.50 = 8.50 x 60

  = 510 seconds

A. By applying the first equation of motion, the speed of the shuttle at the end of 8.50 minutes can be determined by;

v = u + at

where: v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.

u = 0

So that,

v = 14 x 510

 = 7140 m/s

The speed of the shuttle at the end of 8.50 minute is 7.14 Km/s.

B. the distance traveled can be determined by applying second equation of motion.

s = ut + \frac{1}{2}at^{2}

where: s is the distance, u is the initial velocity, a is the acceleration and t is the time.

u = 0

s = \frac{1}{2}at^{2}

  = \frac{1}{2} x 14 x (510)^{2}

 = 7 x 260100

 = 1820700 m

The distance that the shuttle has traveled during the given time is  1820.7 Km.

5 0
2 years ago
Why do plants not need digistive system
WINSTONCH [101]
Humans need a digestive system to do cellular respiration, which produces energy used for growth and movement.

Plants do not need one as they make their own energy through photosynthesis. The process produces glucose, which is a form of energy for the plants.
4 0
3 years ago
Read 2 more answers
consider a sample of gas in a container on a comfortable spring day. the Celsius temperature suddenly doubles, and you transfer
Tasya [4]

Answer:

6.6 atm

Explanation:

Using the general gas law

P₁V₁/T₁ = P₂V₂/T₂

Let P₂ be the new pressure

So, P₂ = P₁V₁T₂/V₂T₁

Since V₂ = 2V₁ , P₁ = 12 atm and T₁ = 273 + t where t = temperature in Celsius

T₂ = 273 + 2t (since its Celsius temperature doubles).

Substituting these values into the equation for P₂, we have

P₂ = P₁V₁(273 + 2t)/2V₁(273 + t)

P₂ = 12(273 + 2t)/[2(273 + t)]

P₂ = 6(273 + 2t)/(273 + t)]

assume t = 30 °C on a comfortable spring day

P₂ = 6(273 + 2(30))/(273 + 30)]

P₂ = 6(273 + 60))/(273 + 30)]

P₂ = 6(333))/(303)]

P₂ = 6.6 atm

7 0
3 years ago
5. What is the mass (m) of an object with a speed (v) of 10 m/s and a momentum
ZanzabumX [31]

Answer:

0.54kg

Explanation:

p=mv

m=p/v

m=5.4/10

=0.54kg

4 0
3 years ago
Other questions:
  • A girl weighs 200 newtons. How<br> much work does she do<br> climbing 10 meters of steps?
    6·2 answers
  • Which vocabulary term is survival of the fittest
    7·1 answer
  • Pls help on this one
    8·2 answers
  • Nearly all physics problems will use the unit m/s^2 for acceleration. Explain why the seconds are squared. Why isn't the unit gi
    10·1 answer
  • On a safari, a team of naturalists sets out toward a research station located 4.63 km away in a direction 38.7 ° north of east.
    14·1 answer
  • a student lift a 25kg mass at vertical distance of 1.6m in a time of 2.0 seconds. a. Find the force needed to lift the mass (in
    12·1 answer
  • Two go-carts, A and B, race each other around a 1.0 track. Go-cart A travels at a constant speed of 20.0 /. Go-cart B accelerate
    9·1 answer
  • A block of mass 2 kg is launched by compressing a spring of force constant 1200 N/m. The block slides on a frictionless surface,
    14·1 answer
  • A 10,000 kg traveling 15m/s strikes a second car which is at rest (not moving). The two stick together and move off with speed o
    15·1 answer
  • How do I calculate the tension in the horizontal string?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!