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Masja [62]
2 years ago
7

What's a material that contains oxygen and silicon??

Chemistry
1 answer:
Maslowich2 years ago
8 0
Sand/quartz or silicon dioxide contains both silicone and oxygen

hope that helps
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When the equation 
galina1969 [7]

Answer:

The least whole number coefficient for HNO₃ is 6

Explanation:

The chemical equation above is the reaction between calcium orthophosphate and nitric acid.

To balance a chemical equation, we have to consider law of conservation of matter which states that matter can neither be created nor destroyed.

What this law implies is that, whatever we have at the reactant side must be equal to whatever is obtainable at the product side.

The above equation is

Ca₃(PO₄)₂ + HNO₃ → Ca(NO₃)₂ + H₃PO₄

To balance the equation, we'll have to check the number of atoms at each side and possibly balance the equation with the number of moles.

The balanced equation is

Ca₃(PO₄)₂ + 6HNO₃ → 3Ca(NO₃)₂ + 2H₃PO₄

From the balanced equation above, we can see that the number of calcium (Ca), Phosphorus (P), Oxygen(O), Nitrogen(N) and hydrogen (H) are balanced at both sides of the equation.

The least number coefficient for HNO₃ is 6

3 0
2 years ago
1.A telescope is a tool that helps people observe distant objects. In the simplest telescope design, incoming light hits a lens
Dahasolnce [82]

Answer:

it is refraction

Explanation:

7 0
2 years ago
Calculate the osmotic pressure of 20 m solution of <br> LiCl at 25C
Soloha48 [4]

Answer:

979 atm

Explanation:

To calculate the osmotic pressure, you need to use the following equation:

π = <em>i </em>MRT

In this equation,

-----> π = osmotic pressure (atm)

-----><em> i</em> = van't Hoff's factor (number of dissolved ions)

-----> M = Molarity (M)

-----> R = Ideal Gas constant (0.08206 L*atm/mol*K)

-----> T = temperature (K)

When LiCl dissolves, it dissociates into two ions (Li⁺ and Cl⁻). Therefore, van't Hoff's factor is 2. Before plugging the given values into the equation, you need to convert Celsius to Kelvin.

<em>i </em>= 2                             R = 0.08206 L*atm/mol*K

M = 20 M                    T = 25°C + 273.15 = 298.15 K

π = <em>i </em>MRT

π = (2)(20 M)(0.08206 L*atm/mol*K)(298.15 K)

π = 979 atm

5 0
2 years ago
What is the primary cause of diffusion? some substances can dissolve in solvents heat added to a substance random internal motio
Nina [5.8K]

Answer:

random internal motion of atoms and molecule

Explanation:

The primary cause of diffusion is the random internal motion of atoms and molecules.

Randomness of atoms and molecules results in diffusion.

  • Diffusion is the movement of particles from a region of high concentration to that of lower concentration.
  • Substances often tend to spread out over the concentration gradient.
  • Therefore, they have this propensity to be randomized.
3 0
2 years ago
Three kilograms of steam is contained in a horizontal, frictionless piston and the cylinder is heated at a constant pressure of
lakkis [162]

Answer:

Final temperature: 659.8ºC

Expansion work: 3*75=225 kJ

Internal energy change: 275 kJ

Explanation:

First, considering both initial and final states, write the energy balance:

U_{2}-U_{1}=Q-W

Q is the only variable known. To determine the work, it is possible to consider the reversible process; the work done on a expansion reversible process may be calculated as:

dw=Pdv

The pressure is constant, so:  w=P(v_{2}-v_{1} )=0.5*100*1.5=75\frac{kJ}{kg} (There is a multiplication by 100 due to the conversion of bar to kPa)

So, the internal energy change may be calculated from the energy balance (don't forget to multiply by the mass):

U_{2}-U_{1}=500-(3*75)=275kJ

On the other hand, due to the low pressure the ideal gas law may be appropriate. The ideal gas law is written for both states:

P_{1}V_{1}=nRT_{1}

P_{2}V_{2}=nRT_{2}\\V_{2}=2.5V_{1}\\P_{2}=P_{1}\\2.5P_{1}V_{1}=nRT_{2}  

Subtracting the first from the second:

1.5P_{1}V_{1}=nR(T_{2}-T_{1})

Isolating T_{2}:

T_{2}=T_{1}+\frac{1.5P_{1}V_{1}}{nR}

Assuming that it is water steam, n=0.1666 kmol

V_{1}=\frac{nRT_{1}}{P_{1}}=\frac{8.314*0.1666*373.15}{500} =1.034m^{3}

T_{2}=100+\frac{1.5*500*1.034}{0.1666*8.314}=659.76 ºC

7 0
3 years ago
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