Answer:
The least whole number coefficient for HNO₃ is 6
Explanation:
The chemical equation above is the reaction between calcium orthophosphate and nitric acid.
To balance a chemical equation, we have to consider law of conservation of matter which states that matter can neither be created nor destroyed.
What this law implies is that, whatever we have at the reactant side must be equal to whatever is obtainable at the product side.
The above equation is
Ca₃(PO₄)₂ + HNO₃ → Ca(NO₃)₂ + H₃PO₄
To balance the equation, we'll have to check the number of atoms at each side and possibly balance the equation with the number of moles.
The balanced equation is
Ca₃(PO₄)₂ + 6HNO₃ → 3Ca(NO₃)₂ + 2H₃PO₄
From the balanced equation above, we can see that the number of calcium (Ca), Phosphorus (P), Oxygen(O), Nitrogen(N) and hydrogen (H) are balanced at both sides of the equation.
The least number coefficient for HNO₃ is 6
Answer:
979 atm
Explanation:
To calculate the osmotic pressure, you need to use the following equation:
π = <em>i </em>MRT
In this equation,
-----> π = osmotic pressure (atm)
-----><em> i</em> = van't Hoff's factor (number of dissolved ions)
-----> M = Molarity (M)
-----> R = Ideal Gas constant (0.08206 L*atm/mol*K)
-----> T = temperature (K)
When LiCl dissolves, it dissociates into two ions (Li⁺ and Cl⁻). Therefore, van't Hoff's factor is 2. Before plugging the given values into the equation, you need to convert Celsius to Kelvin.
<em>i </em>= 2 R = 0.08206 L*atm/mol*K
M = 20 M T = 25°C + 273.15 = 298.15 K
π = <em>i </em>MRT
π = (2)(20 M)(0.08206 L*atm/mol*K)(298.15 K)
π = 979 atm
Answer:
random internal motion of atoms and molecule
Explanation:
The primary cause of diffusion is the random internal motion of atoms and molecules.
Randomness of atoms and molecules results in diffusion.
- Diffusion is the movement of particles from a region of high concentration to that of lower concentration.
- Substances often tend to spread out over the concentration gradient.
- Therefore, they have this propensity to be randomized.
Answer:
Final temperature: 659.8ºC
Expansion work: 3*75=225 kJ
Internal energy change: 275 kJ
Explanation:
First, considering both initial and final states, write the energy balance:
Q is the only variable known. To determine the work, it is possible to consider the reversible process; the work done on a expansion reversible process may be calculated as:
The pressure is constant, so: 
(There is a multiplication by 100 due to the conversion of bar to kPa)
So, the internal energy change may be calculated from the energy balance (don't forget to multiply by the mass):
On the other hand, due to the low pressure the ideal gas law may be appropriate. The ideal gas law is written for both states:
Subtracting the first from the second:
Isolating 
:
Assuming that it is water steam, n=0.1666 kmol
ºC
