The third compound will have a suffix of -yne. Alkynes are molecules that contain triple bonds.
Conduction which is a method of heat transfer where heat is transfer directly from one medium to another.
94.63 mg/L as a unit of density is equivalent to 9.463 × 10-⁵ g/mL.
<h3>What is density?</h3>
Density is a measure of the mass of matter contained by a unit volume.
Density of a substance can be calculated by dividing the mass of the substance in grams by its volume in milllilitres. This means that the unit of measurement for density is g/mL.
However, the conversion factor of g/mL to mg/L is as follows:
1 gram/millilitre = 1000000 milligrams/litre
94.63 mg/L = 94.63 ÷ 1000000
= 9.463 × 10-⁵ g/mL
Therefore, 94.63 mg/L as a unit of density is equivalent to 9.463 × 10-⁵ g/mL.
Learn more about density at: brainly.com/question/15164682
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Answer:
25.0 mL
Explanation:
1. Gather the information in one place.
MM: 98.00 74.09
2H3PO4 + 3Ca(OH)2 → Ca3(PO4)2 + 6H2O
m/g: 8.85 15.76
V/mL: 350.0 550
2. Moles of H3PO4
n = 8.85 g × (1 mol/98.00 g) = 0.09031 mol H3PO4
3. Moles of Ca(OH)2
n = 15.76 g × (1 mol/74.09 g) = 0.2126 mol Ca(OH)2
4. Moles of Ca(OH)2 in 25.0 mL Solution
n = 0.2126 mol × (25.0 mL/550 mL) = 0.009 663 mol Ca(OH)2
5. Moles of H3PO4 needed
From the balanced equation, the molar ratio is 2 mol H3PO4: 3 mol Ca(OH)2
n = 0.009 663 mol Ca(OH)2 × (2 mol H3PO4/3 mol Ca(OH)2)
= 0.006 442 mol H3PO4
6. Volume of H3PO4
V = 0.006 442 mol ×( 350.0 mL/0.09031 mol) = 25.0 mL H3PO4
It will take 25.0 mL of the H3PO4 solution to neutralize 25.0 mL of the Ca(OH)2 solution.
