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2 years ago

Given: NaCl + AgNO3 -> AgCl + NaNO3

Chemistry

2 answers:

vodomira [7]2 years ago

6 0

Answer:

The answer to your question is 0.49 moles of AgCl

Explanation:

Data

mass of AgNO₃ = 83 g

moles of AgCl = ?

mass of NaCl = excess

Balanced chemical reaction

NaCl + AgNO₃ ⇒ AgCl + NaNO₃

Process

1.- Calculate the molar mass of AgNO₃

AgNO₃ = 108 + 14 + (16 x 3) = 170 g

2.- Convert the grams of AgNO₃ to moles

170 g of AgNO₃ --------------- 1 mol

83 g of AgNO₃ -------------- x

x = (83 x 1) / 170

x = 0.49 moles

3.- Calculate the moles of AgCl

1 mol of AgCl ------------ 1 mol of AgNO₃

x mol of AgCl ------------ 0.49 moles of AgNO₃

x = (0.49 x 1)/1

x = 0.49 moles of AgCl

Kay [80]2 years ago

4 0

Answer:

.49

Explanation:

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3 years ago

How many moles are in 1.51x10^26 atoms of xenon (Xe)? Please and thank you :)!!

RoseWind [281]

<h3>Answer:</h3>

251 mol Xe

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.51 × 10²⁶ atoms Xe

[Solve] moles Xe

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 1.51 \cdot 10^{26} \ atoms \ Xe(\frac{1 \ mol \ Xe}{6.022 \cdot 10^{23} \ atoms \ Xe})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 250.747 \ mol \ Xe$

<u>Step 4: Check</u>

<em>Follow sig fig rule and round. We are given 3 sig figs.</em>

250.747 mol Xe ≈ 251 mol Xe

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2 years ago