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3 years ago

Given: NaCl + AgNO3 -> AgCl + NaNO3

Chemistry

2 answers:

vodomira [7]3 years ago

6 0

Answer:

The answer to your question is 0.49 moles of AgCl

Explanation:

Data

mass of AgNO₃ = 83 g

moles of AgCl = ?

mass of NaCl = excess

Balanced chemical reaction

NaCl + AgNO₃ ⇒ AgCl + NaNO₃

Process

1.- Calculate the molar mass of AgNO₃

AgNO₃ = 108 + 14 + (16 x 3) = 170 g

2.- Convert the grams of AgNO₃ to moles

170 g of AgNO₃ --------------- 1 mol

83 g of AgNO₃ -------------- x

x = (83 x 1) / 170

x = 0.49 moles

3.- Calculate the moles of AgCl

1 mol of AgCl ------------ 1 mol of AgNO₃

x mol of AgCl ------------ 0.49 moles of AgNO₃

x = (0.49 x 1)/1

x = 0.49 moles of AgCl

Kay [80]3 years ago

4 0

Answer:

.49

Explanation:

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Answer:

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Artyom0805 [142]

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