5.6 Al(OH)3
5.6 Al, 16.8 O, 16.8 H
16.8 mols of oxegyn in 5.6 mols of Al(OH)3
Answer:
O2+H2 → H2O
become→zero to−2
∵ it will be reduced and oxidation state of H
2
becomes zero to +1 it will be oxidised.
∴ reaction will be redox
Explanation:
please mark me as brainalist
sp3d2 hybridization has 1s, 3p and 2d orbitals, that undergo intermixing to form 6 identical sp3d2 hybrid orbitals. These 6 orbitals are directed towards the corners of an octahedron. They are inclined at an angle of 90 degrees to one another.
<h3>Which orbitals hybridize to form hybrid orbitals?</h3>
For each carbon, one 2s orbital and two 2p orbitals hybridize to form three sp2 orbitals. These hybridized orbitals align themselves in the trigonal planar structure. For each carbon, two of these sp orbitals bond with two 1s hydrogen orbitals through s-sp orbital overlap.
<h3 /><h3>What is sp3d2 hybridization?</h3>
Intermixing of one 's', three 'p' and two 'd' orbitals of almost same energy by giving six identical and degenerate hybrid orbitals is called sp3d2 hybridization. These six sp3d2 orbitals are arranged in octahedral symmetry by making 90° angles to each other.
Learn more about hybridization here:
<h3 /><h3>
brainly.com/question/1604211</h3><h3 /><h3>#SPJ4</h3>
Molar mass is 28+32 = 60
So take 3.4 x 10^-7/60 and get about 5.7 x 10^-9
Answer:
0.26g of NaCl is the maximum mass that could be produced
Explanation:
Based on the reaction:
HCl + NaOH → NaCl + H₂O
<em>Where 1 mol of HCl reacts per mol of NaOH to produce 1 mol of NaCl</em>
<em />
To solve this question we need to find <em>limiting reactant. </em>The moles of limiting reactant = Moles of NaCl produced:
<em>Moles HCl -Molar mass: 36.46g/mol-:</em>
0.365g HCl * (1mol / 36.46g) = 0.010 moles HCl
<em>Moles NaOH -Molar mass: 40g/mol-:</em>
0.18g NaOH * (1mol / 40g) = 0.0045 moles NaOH
As the reaction is 1:1 and moles NaOH < moles HCl, limiting reactant is NaOH and maximum moles produced of NaCl are 0.0045 moles.
The mass of NaCl is:
<em>Mass NaCl -Molar mass: 58.44g/mol-:</em>
0.0045 moles * (58.44g/mol) =
<h3>0.26g of NaCl is the maximum mass that could be produced</h3>
