Answer:
a = -2 or a = -5
Step-by-step explanation:
We want
. We can subtract 2 from both sides of this equation to get
. We can factor this to get that
. When the product of two numbers is equal to zero, one of the numbers must be equal to zero. This means that either a + 2 = 0, in which case a = -2, or a + 5 = 0, in which case a = -5.
Answer:
3x-2y
Step-by-step explanation:
log10^(3x-2y)
We know the base is base 10 since it is not written
log10 10^(3x-2y)
The log10 10 cancels
3x-2y
Answer:
(E) 0.71
Step-by-step explanation:
Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.
So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:
P(A'∩B') = 1 - P(A∪B)
it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.
Therefore, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12
So, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.25 + 0.16 - 0.12
P(A∪B) = 0.29
Finally, P(A'∩B') is equal to:
P(A'∩B') = 1 - P(A∪B)
P(A'∩B') = 1 - 0.29
P(A'∩B') = 0.71
Answer:
y = 28 - x
Step-by-step explanation:
The variable x represents how many buttons Paula had before giving 28 away and the variable y represents how many buttons she has now.
Answer:
The Answer would be 1.4f-18
Step-by-step explanation:
-2.3f+0.9f-14-4
then you do
-1.4f-14-4
Then u would get 1.4f-18.