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BabaBlast [244]
3 years ago
15

How do we use rock and mineral resources daily?

Physics
2 answers:
aalyn [17]3 years ago
7 0
Salt...I think salt is a mineral
nikitadnepr [17]3 years ago
4 0
Well minerals are in the water we drink every Day, even the food we eat. Minerals are contained in rocks so there for both are important to life
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A 20-kg cart travels at 20 m/s in a circle with a radius of 20 m. What is the centripetal force?
Vlad1618 [11]

Centripetal force = (mass) x (speed)² / (radius)

                           = (20 kg) x (20 m/s)² / (20 m)

                           = (20 x 20 / 20)  (kg-meter/sec²)

                           = 20 newtons


5 0
3 years ago
Read 2 more answers
An iron nail is driven into a block of ice by a single blow of a hammer. The hammerhead has a mass of 0.5 kg and an initial spee
larisa [96]

Answer:

The ice melts mass is:

m_g=7.6x10^{-3} g

Explanation:

Kinetic Energy  

K_E = 1/2*m*v^2

K_E = 1/2*0.5kg*(3.2m/s)^2

K_E=2.56 kg*m^2/s^2

Heat gained by ice= mass(g) x 80 cal

( 1 cal = 4.184 *10^7er or g cm^2/ sec^2)

Assuming no loss in heat,  in the motion so both continue with temperature 0~C

To find so the mass (gm) of ice melted

m_g= 1/2 *(0.5*1000)*(3.2m/s)^2* 100*100 / (80*4.184*10^7)

m_g=7.6x10^{-3} g

5 0
3 years ago
A uniform meterstick of mass 0.20 kg is pivoted at the 40 cm mark. where should one hang a mass of 0.50 kg to balance the stick?
Tcecarenko [31]
The weight of the meterstick is:
W=mg=0.20 kg \cdot 9.81 m/s^2 = 1.97 N
and this weight is applied at the center of mass of the meterstick, so at x=0.50 m, therefore at a distance 
d_1 = 0.50 m - 0.40 m=0.10 m
from the pivot.
The torque generated by the weight of the meterstick around the pivot is:
M_w = W d_1 = (1.97 N)(0.10 m)=0.20 Nm

To keep the system in equilibrium, the mass of 0.50 kg must generate an equal torque with opposite direction of rotation, so it must be located at a distance d2 somewhere between x=0 and x=0.40 m. The magnitude of the torque should be the same, 0.20 Nm, and so we have:
(mg) d_2 = 0.20 Nm
from which we find the value of d2:
d_2 =  \frac{0.20 Nm}{mg}= \frac{0.20 Nm}{(0.5 kg)(9.81 m/s^2)}=0.04 m

So, the mass should be put at x=-0.04 m from the pivot, therefore at the x=36 cm mark.
4 0
3 years ago
A fire is burning in a fireplace. Where is the radiation?
mrs_skeptik [129]
I think it’s A.
........
5 0
2 years ago
MRU(movimiento rectilineo uniforme) un movil viaja en linea recta con una velocidad media de 12metros /segundos durante 9segundo
liubo4ka [24]

Answer:

a) 141.6m

b) 8.4m/s

Explanation:

a) to find the total displacement you use the following formula for each trajectory. Next you sum the results:

x_1=v_1t_1=(12m/s)(9s)=108m\\\\x_2=v_2t_2=(4.8m/s)(7s)=33.6m\\\\x_T=x_1+x_2=108m+33.6m=141.6m

hence, the total distance is 141.6m

b) the mean velocity of the total trajectory is given by:

v_m=\frac{v_1+v_2}{2}=\frac{12m/s+4.8m/s}{2}=8.4\frac{m}{s}

hence, the mean velocity is 8.4 m/s

8 0
3 years ago
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