A 'displacement' always consists of a magnitude and a direction. The two cars you just described have displacements with the same magnitude ... 5 km. But if they didn't both drive in the same direction, then their displacements are different.
Remember:
-- 10 m/s² up and 10 m/s² down are different accelerations
-- 30 mph East and 30 mph West are the same speed but different velocity.
-- 5 km North and 5 km South are the same distance but different displacement.
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The y-component of the acceleration is 
Explanation:
The y-component of the ice skater acceleration can be calculated with the equation
where
is the y-component of the final velocity
is the y-component of the initial velocity
t is the time elapsed
Here we have:
- Initial velocity is
at 
, so its y-component is 
- Final velocity is
at 
, so its y-component is 
The time elapsed is
t = 8.33 s
Therefore, the y-component of the acceleration is
Learn more about acceleration:
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The first thing you should do for this case is to find the horizontal and vertical components of the forces acting on the body.
We have then:
Horizontal = 9-9.2cos (58) = 4.124742769 N.
Vertical = 9.2sin (58) = 7.802042485 N
Then, the resulting net force is:
F = √ ((4.124742769) ^ 2 + (7.802042485) ^ 2) = 8.825268826 N
Then by definition:
F = m * a
Clearing the acceleration:
a = F / m
a = (8.825268826) / (3.0) = 2.941756275 m / s ^ 2
answer:
The magnitude of the body's acceleration is
2.941756275 m / s ^ 2
