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Delvig [45]
3 years ago
8

Why is it impossible to "defy gravity“?

Physics
1 answer:
Kamila [148]3 years ago
6 0

Answer:

i belive its d

Explanation:

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What vertical distance Δy does a free-falling particle travel from the moment it starts to the moment it reaches a speed of 7.9
mr_godi [17]

Answer:

3.2 m

Explanation:

The equation to use to solve this problem is:

v_f^2 = v_i^2 + 2 a \Delta y

where

v_f is the final velocity

v_i is the initial velocity

a is the acceleration

\Delta y is the distance covered

For the particle in free-fall in this problem, we have

v_i = 0 (it starts from rest)

v_f = 7.9 m/s

g=9.8 m/s^2 (acceleration due to gravity)

By re-arranging the equation, we can find the distance travelled:

\Delta y = \frac{v_f^2 -v_i^2}{2a}=\frac{(7.9 m/s)^2-0^2}{2(9.8 m/s^2)}=3.2 m

5 0
3 years ago
Which statement is a characteristic of a concave lens?
Trava [24]
D. it is thickest in the middle
3 0
3 years ago
Read 2 more answers
What is the relationship between matter and energy as it changes states of matter (phase changes?)
AlekseyPX

These energy exchanges are not changes in kinetic energy. They are changes in bonding energy between the molecules. If heat is coming into a substance during a phase change, then this energy is used to break the bonds between the molecules of the substance. The example we will use here is ice melting into water.

7 0
3 years ago
A woman holds a book by placing it between her hands such that she presses at right angles to the front and back covers. The boo
In-s [12.5K]

Answer:

Explanation:

In order to solve this problem we need to make a free body diagram of the book and the forces that interact on it. In the picture below you can see the free body diagram with these forces.

The person holding the book is compressing it with his hands, thus exerting a couple of forces of equal magnitude and opposite direction with value F.

Now the key to solving this problem is to analyze the equilibrium condition (Newton's third law) on the x & y axes.

To find the weight of the book we simply multiply the mass of the book by gravity.

W = m*g

W = 1.3[kg] * 9.81[m/s^2]

W = 12.75 [N]

7 0
3 years ago
A 170 kg astronaut (including space suit) acquires a speed of 2.25 m/s by pushing off with his legs from a 2600 kg space capsule
saw5 [17]

Explanation:

Mass of the astronaut, m₁ = 170 kg

Speed of astronaut, v₁ = 2.25 m/s

mass of space capsule, m₂ = 2600 kg

Let v₂ is the speed of the space capsule. It can be calculated using the conservation of momentum as :

initial momentum = final momentum

Since, initial momentum is zero. So,

m_1v_1+m_2v_2=0

170\ kg\times 2.25\ m/s+2600\ kg\times v_2=0

v_2=-0.17\ m/s

So, the change in speed of the space capsule is 0.17 m/s. Hence, this is the required solution.

8 0
3 years ago
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