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adoni [48]
3 years ago
11

PLEAS HELP.

Physics
1 answer:
koban [17]3 years ago
8 0

<span>A: put an atom on a poster in the exhibit
     Good luck.  The poster itself is made of trillions of trillions of trillions
     of atoms.  You could not see the extra one any easier than you could
     see the ones that are already there, and even if you could, it would be
     lost in the crowd.
 
B: use a life size drawing of an atom
     Good luck.  Nobody has ever seen an atom.  Atoms are too small
     to see.  That's a big part of the reason that nobody knew they exist
     until less than 200 years ago.

D: set up a microscope so that visitors can view atoms
     Good luck.  Atoms are way too small to see with a microscope.

</span><span><span>C: Display a large three dimensional model of an atom.
    </span> </span>Finally !  A suggestion that makes sense.
     If something is too big or too small to see, show a model of it
         that's just the right size to see.

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Determine the amount of potential energy of a 5N book that is 1.5m high on a shelf.
Alex73 [517]

Answer:

Potential energy of book = 7.5 J

Explanation:

Given:

Weight of book = 5 N

Height of shelf = 1.5 meter

Find:

Potential energy of book

Computation:

Weight = Mass x Acceleration of gravity

Mass x Acceleration of gravity = 5 N

Potential energy = Mass x Acceleration of gravity x Height

Potential energy of book = Mass x Acceleration of gravity x Height

We know that;

Mass x Acceleration of gravity = 5 N

So,

Potential energy of book = 5 x 1.5

Potential energy of book = 7.5 J

3 0
3 years ago
An electron with speed 2.45 x 10^7 m/s is traveling parallel to a uniform electric field of magnitude 1.18 x 10^4N/C . How much
cupoosta [38]

Answer:

time will elapse before it return to  its staring point is 23.6 ns

Explanation:

given data

speed u = 2.45 × 10^{7} m/s

uniform electric field E = 1.18 × 10^{4} N/C

to find out

How much time will elapse before it returns to its starting point

solution

we find acceleration first by electrostatic force that is

F = Eq

here

F = ma by newton law

so

ma = Eq

here m is mass , a is acceleration and E is uniform electric field and q is charge of electron

so

put here all value

9.11 × 10^{-31} kg ×a = 1.18 × 10^{4} × 1.602 × 10^{-19}

a = 20.75 × 10^{14} m/s²

so acceleration is 20.75 × 10^{14} m/s²

and

time required by electron before come rest is

use equation of motion

v = u + at

here v is zero and u is speed given and t is time so put all value

2.45 × 10^{7} = 0 + 20.75 × 10^{14} (t)

t = 11.80 × 10^{-9} s

so time will elapse before it return to  its staring point is

time = 2t

time = 2 ×11.80 × 10^{-9}

time is 23.6 × 10^{-9} s

time will elapse before it return to  its staring point is 23.6 ns

7 0
3 years ago
Consider a book that weighs 15 N at rest on a flat table. How many newtons of support does the table provide?
zysi [14]
<span>The support force is 15 N. The net force on the book is zero.</span>
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1) Momenum is
adelina 88 [10]

Answer:

momentum formula = Mass × Velocity

3 0
3 years ago
Sally Sizzle builds a circuit by connecting three resistors in parallel with a 9V battery. The current in this circuit is 3.6 am
Andru [333]

Then answer is C 9 ohms

7 0
3 years ago
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