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3 years ago

PLEAS HELP.

1 answer:

8 0

A: put an atom on a poster in the exhibit
 Good luck. The poster itself is made of trillions of trillions of trillions
 of atoms. You could not see the extra one any easier than you could
 see the ones that are already there, and even if you could, it would be
 lost in the crowd.

B: use a life size drawing of an atom
 Good luck. Nobody has ever seen an atom. Atoms are too small
 to see. That's a big part of the reason that nobody knew they exist
 until less than 200 years ago.

D: set up a microscope so that visitors can view atoms
 Good luck. Atoms are way too small to see with a microscope.

C: Display a large three dimensional model of an atom.
 Finally ! A suggestion that makes sense.
 If something is too big or too small to see, show a model of it
 that's just the right size to see.

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Four boxes of increasing size and weight must be pushed up a ramp. To push the boxes at the same speed, what must you do?

kari74 [83]

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4 years ago

Read 2 more answers

For your answer to this problem, just type in the numerical magnitude of the momentum - no units.

stepan [7]

Answer:

120 kg•m/s.

Explanation:

From the question given above, the following data were obtained:

Case 1

Mass of object = M

Velocity of object = V

Momentum = 15 kg•m/s

Case 2

Mass of object = 2M

Velocity of object = 4V

Momentum = ?

Momentum is defined as follow:

Momentum = mass × velocity

The momentum of object in case 2 can be obtained as follow:

From case 1

Momentum = mass × velocity

15 = M × V

15 = MV ....... (1)

From case 2:

Momentum = mass × velocity

Momentum = 2M × 4V

Momentum = 8MV ....... (2)

Finally , substitute the value of MV in equation 1 into equation 2.

Momentum = 8MV

MV = 15

Momentum = 8 × 15

Momentum = 120 kg•m/s

Therefore, an object with a mass of 2M and 4V would have a momentum of 120 kg•m/s

3 0

3 years ago

If Ms. Ramirez drops a watermelon from the top of the second-floor fire escape outside her room, and it takes 1.5 seconds to hit

mamaluj [8]

The velocity of the watermelon as it hits the ground is 14.715 m/s.

Given the data in the question;

Since the Watermelon was dropped from rest,

Initial velocity of the Watermelon; $u = 0m/s$

Time taken for the Watermelon to hit the ground; $t = 1.5s$

We know that, Acceleration due to gravity; $g = 9.81 m/s^2$

Now, we determine the velocity of the watermelon as it hits the ground which is the final velocity.

From the First Equation of Motion:

$v = u + at$

Now, under gravity, acceleration ''a" will Acceleration due to gravity; $g = 9.81m/s^2$ , "v" is the final velocity, "u" is the initial velocity and "t" is the time taken.