Explanation:
Given that,
Electrostatic force, 
Distance, 
(a)
, q is the charge on the ion


(b) Let n is the number of electrons are missing from each ion. It can be calculated as :


n = 2
Hence, this is the required solution.
You'd get an extra 40/60 of the energy, or 2/3. Multiply 5/3 by the required energy to get the actual consumption.
Answer:
A- Martin brings his friends home to meet grandpa.
Explanation:
took the test.
Answer:
(a) 4.21 m/s
(b) 24.9 N
Explanation:
(a) Draw a free body diagram of the object when it is at the bottom of the circle. There are two forces on the object: tension force T pulling up and weight force mg pulling down.
Sum the forces in the radial (+y) direction:
∑F = ma
T − mg = m v² / r
v = √(r (T − mg) / m)
v = √(0.676 m (54.7 N − 1.52 kg × 9.8 m/s²) / 1.52 kg)
v = 4.21 m/s
(b) Draw a free body diagram of the object when it is at the top of the circle. There are two forces on the object: tension force T pulling down and weight force mg pulling down.
Sum the forces in the radial (-y) direction:
∑F = ma
T + mg = m v² / r
T = m v² / r − mg
T = (1.52 kg) (4.21 m/s)² / (0.676 m) − (1.52 kg) (9.8 m/s²)
T = 24.9 N
Answer:
15 m/s
Explanation:
Speed(m/s) = distance(m)/time(s)
distance = 216 km = 216,000 m
time = 4 hours = 14,400 s
speed = 216000/14400 = 15 m/s