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3 years ago

Plz help with dis science

Physics

1 answer:

grandymaker [24]3 years ago

8 0

I'll give you some of them, but I want you to promise to
look them up, either on line or in a book, and read more
about them, even after you have the answers.

This whole sheet is talking about the "states" of matter,
and changes between the states.

There are three "states" of matter:
-- solid like ice
-- liquid like runny water
-- gas, like steam

1). When a substance changes from one to another,
that's a "change of state".

2). Which of these states has a definite shape and volume ?
(It doesn't make puddle, and it doesn't fill up the room. It's "solid".)

3). You know this one. What is it when ice changes to runny water ?

4). Which state can you put into a jar, and it gets round like the jar
but it doesn't fill up the jar ?

5). You know this. What is it when runny water changes to ice ?

6). Which state fills up anything you put it into ?

7). I don't know this one. It's either endothermic or exothermic.
I can never get these straight.

8). Same as #6. Which state fills up anything you put it into ?

9). I don't know the term that includes both boiling and evaporation.

10). This is the opposite of #7.
As I said, I can never get these straight.

11). Changing from a gas to a liquid, like steam to water,
or breathing fog onto a mirror, is "condensation".

12). This is interesting. If you have a lump of dry ice on the table
and it melts, there's no puddle around it ! It goes directly from solid
to carbon dioxide gas, and never forms liquid. That process is called "sublimation", and we say that the dry ice "sublimes".

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Two blocks are connected by a light string that passes over two frictionless pulleys. The block of mass m2 is attached to a spri

irina1246 [14]

(BELOW YOU CAN FIND ATTACHED THE IMAGE OF THE SITUATION)

Answer:

$d=\frac{2g(m1-m2)}{k}$

Explanation:

For this we're going to use conservation of mechanical energy because there are nor dissipative forces as friction. So, the change on mechanical energy (E) should be zero, that means:

$E_{i}=E_{f}$

$K_{i}+U_{i}=K_{f}+U_{f}$ (1)

With $K_{i}$ the initial kinetic energy, $U_{i}$ the initial potential energy, $K_{f}$ the final kinetic energy and $U_{f}$ the final potential energy. Note that initialy the masses are at rest so $K_{i} = 0$ , when they are released the block 2 moves downward because m2>m1 and finally when the mass 2 reaches its maximum displacement the blocks will be instantly at rest so $K_{f} =0$ . So, equation (1) becomes:

$U_{i}=U_{f}$ (2)

At initial moment all the potential energy is gravitational because the spring is not stretched so $U_{i}=U_{gi}$ and at final moment we have potential gravitational energy and potential elastic energy so $U_{f}=U_{gf}+U_{ef}$ , using this on (2)

$U_{gi}=U_{gf}+U_{ef}$ (3)

Additional if we define the cero of potential gravitational energy as sketched on the figure below (See image attached), $U_{gi}=0$ and we have by (3) :

$0= U_{gf}+U_{ef}$ (4)

Now when the block 1 moves a distance d upward the block 2 moves downward a distance d too (to maintain a constant length of the rope) and the spring stretches a distance d, so (4) is:

$0=-m1gd+m2gd+\frac{kd^{2}}{2}$

dividing both sides by d

$0=-m1g+m2g+\frac{kd}{2}$

$g(m1-m2)= \frac{kd}{2}$

$d=\frac{2g(m1-m2)}{k}$ , with k the constant of the spring and g the gravitational acceleration.

7 0

3 years ago

Assuming the bar has no weight where does the fulcrum (the top point of the tringle) need to be positioned for the two sides to

Inessa05 [86]

Fulcrum need to be positioned balanced with weight on both the sides following law of lever.

What is the physical law of the lever?

It is the foundation for issues with weight and balance. According to this rule, a lever is balanced when the weight multiplied by the arm on one side of the fulcrum, which serves as the pivot point for the device, equals the weight multiplied by the arm on the opposing side.
The lever is balanced, in other words, when the sum of the moments about the fulcrum is zero.
The situation in which the positive moments (those attempting to turn the lever clockwise) equal the negative moments is known as this (those that try to rotate it counterclockwise).
Moving the weights closer to or away from the fulcrum, as well as raising or lowering the weights, can alter the balance point, or CG, of the lever.

Learn more about the Fulcrum with the help of the given link:

brainly.com/question/16422662

#SPJ4

3 0

1 year ago

According to Ohm's law, a circuit with a high resistance _____. will have a low electric current will have a high electric curre

lyudmila [28]

Remark
When you are asked a question like this, the first thing to do is search out a formula and put some limits on it.

Formula
I = E/R which comes from E = IR. To get to the derived formula, divide both sides by R
E/R = I*R/R
E/R = I

Discussion
This is an inverse relationship. That means that as one goes up the other one will go down.

So in this case you keep E constant and you manipulate R and look at your results for I

Case 1
Let us say that E = 10 volts
Let us also say the R = 10 ohms

I = E/R
I = 10/10
I = 1 ohm

Case Two
Let's raise the Resistance to 100 ohms
E = 10
R = 100
I = 10/100 = 0.1

Conclusion
As the Resistance goes up, the current goes down. Answer: A

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Alenkasestr [34]

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