Answer:
The minimum volume requirement for the granite stones is 1543.64 cm³
Explanation:
1 granite stone weighs 10 denarium
100 granted stones will weigh 1000 denarium
1 denarium = 3.396g
1000 denarium = 3396g.
But we're told that 20% of material is lost during the making of these stones.
This means the mass calculated represents 80% of the original mass requirement, m.
80% of m = 3396
m = 3396/0.8 = 4425 g
This mass represents the minimum mass requirement for making the stones.
To now obtain the corresponding minimum volume requirement
Density = mass/volume
Volume = mass/density = 4425/2.75 = 1543.64 cm³
Hope this helps!!!
Answer:
![\dot m = 2.74 kg/s](https://tex.z-dn.net/?f=%5Cdot%20m%20%3D%202.74%20kg%2Fs)
Explanation:
given data:
pressure 1 MPa
diameter of pipe = 30 cm
average velocity = 10 m/s
area of pipe![= \frac[\pi}{4}d^2](https://tex.z-dn.net/?f=%20%3D%20%5Cfrac%5B%5Cpi%7D%7B4%7Dd%5E2)
![= \frac{\pi}{4} 0.3^2](https://tex.z-dn.net/?f=%20%3D%20%5Cfrac%7B%5Cpi%7D%7B4%7D%200.3%5E2)
A = 0.070 m2
WE KNOW THAT mass flow rate is given as
![\dot m = \rho A v](https://tex.z-dn.net/?f=%5Cdot%20m%20%3D%20%5Crho%20A%20v)
for pressure 1 MPa, the density of steam is = 4.068 kg/m3
therefore we have
![\dot m = 4.068 * 0.070* 10](https://tex.z-dn.net/?f=%5Cdot%20m%20%3D%204.068%20%2A%200.070%2A%2010)
![\dot m = 2.74 kg/s](https://tex.z-dn.net/?f=%5Cdot%20m%20%3D%202.74%20kg%2Fs)
Answer:
The main difference between the bs2 and bs3 engine is to present in the catalytic converter. And in bs2 engines the catalytic converter is does not used for the formation of hc and co. In bs3 engine there is no harmful emissions in the hc and co