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eduard
4 years ago
9

A signal containing both a 5k Hz and a 10k Hz component is passed through a low-pass filter with a cutoff frequency of 4k Hz. Wh

ich component(s) will be attenuated? g
Engineering
1 answer:
abruzzese [7]4 years ago
3 0

Answer:

The 5 kHz signal will be less attenuated and the 10 kHz will be completely attenuated.

Low Pass Filter:

The purpose of a filter is to remove the undesired frequency components in a signal. A low-pass filter is one in which we allow low frequencies components to pass through it and block the higher frequency components. The frequency  where it starts to attenuate the signal is called cut-off frequency.

Explanation:

We have a signal that contains 5 kHz and 10 kHz frequency component.

The cut-off frequency is 4 kHz which means the filter will attenuate the frequency components of 4 kHz or greater than that.

So, in theory both 5 kHz and 10 kHz frequency components will be attenuated.

But filters are not ideal and they usually have a little margin also called roll off which means it will allow some of the frequency components greater than cut-off frequency of 4 kHz.

Conclusion:

So to conclude, the 5 kHz signal will be less attenuated and the 10 kHz will be completely attenuated.

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3 years ago
Discuss the differences between conduction and convective heat transfer.
FrozenT [24]

Answer:

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Explanation:

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3 years ago
Problem 4.079 SI A rigid tank whose volume is 3 m3, initially containing air at 1 bar, 295 K, is connected by a valve to a large
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Answer:

Q_{cv} = -1007.86kJ

Explanation:

Our values are,

State 1

V=3m^3\\P_1=1bar\\T_1 = 295K

We know moreover for the tables A-15 that

u_1 = 210.49kJ/kg\\h_i = 295.17kJkg

State 2

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u_2 = 228.42kJ/kg

We need to use the ideal gas equation to estimate the mass, so

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m_2 = \frac{1bar*100kPa/6bar(3m^3)}{0.287kJ/kg.K(320k)}

m_2 = 19.59kg

We only need to apply a energy balance equation:

Q_{cv}+m_ih_i = m_2u_2-m_1u_1

Q_{cv}=m_2u_2-m1_u_1-(m_2-m_1)h_i

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Q_{cv} = -1007.86kJ

The negative value indidicates heat ransfer from the system

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