The grams of Na that are needed to complete to react with 40..0 g of O2 is calculated as below
find the moles of O2 used = mass/molar mass
= 40 g/32g/mol = 1.25 moles
write the reacting equation
4Na+ O2 = 2Na2O
by use of mole ratio between Na to O2 which is 4 :1
the moles of Na = 1.25 x 4 = 5 moles
mass of Na = mass x molar mass
= 5 moles x 23 g /mol= 115 moles
Answer:
either a car or a rock
Explanation:
because the rock can weigh more than the car , and vice-versa with the car weighing more than the rock
Answer:
607 ppm
Explanation:
In this case we can start with the <u>ppm formula</u>:
If we have a solution of <u>0.0320 M</u>, we can say that in 1 L we have 0.032 mol of , because the molarity formula is:
In other words:
If we use the <u>atomic mass</u> of (19 g/mol) we can convert from mol to g:
Now we can <u>convert from g to mg</u> (1 g= 1000 mg), so:
Finally we can <u>divide by 1 L</u> to find the ppm:
<u>We will have a concentration of 607 ppm.</u>
I hope it helps!
Answer:
It decreases.
Explanation:
Due to changes in the Coulombic force, the protons within the nucleus of the ion have a much easier time pulling at one fewer electrons. This way, the electrons are pulled closer to the center, causing the radius to decrease.
Answer: At temperature of 269 K the gas would occupy 1.33 L at 217 kPa
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = 147 kPa
= final pressure of gas = 217 kPa
= initial volume of gas = 1.8 L
= final volume of gas = 1.33 L
= initial temperature of gas =
= final temperature of gas = ?
Now put all the given values in the above equation, we get:
Thus at 269 K temperature the gas would occupy 1.33 L at 217 kPa