1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sukhopar [10]
2 years ago
14

A test charge is placed at a distance of 3.5 meters from a charge of 8.7 × 10-9 coulombs. What is the electric field strength at

the test charge? (k = 9.0 × 109 newton·meter2/coulomb2) 6.4 newtons/coulomb 8.7 newtons/coulomb 3.5 newtons/coulomb 9.0 newtons/coulomb Done
Physics
1 answer:
zavuch27 [327]2 years ago
8 0
In order to calculate the electric field strength, we may use the formula:
E = kQ/d²
Where Q is the charge and d is the distance between the charge and the test charge. Substituting the values into the equation:
E = (9 x 10⁹)(8.7 x 10⁻⁹) / (3.5²)
E = 6.39 Newtons per coulomb

Therefore, the answer is 6.4 Newtons/coulomb
You might be interested in
A wire carrying a 29.0 A current passes between the poles of a strong magnet such that the wire is perpendicular to the magnet's
Dmitrij [34]

Answer:

2.59 T

Explanation:

Parameters given:

Current flowing through the wire, I = 29 A

Angle between the magnetic field and wire, θ = 90°

Magnetic force, F = 2.25 N

Length of wire, L = 3 cm = 0.03 m

The magnetic force, F, is related to the magnetic field, B, by the equation below:

F = I * L * B * sinθ

Inputting the given parameters:

2.25 = 29 * 0.03 * B * sin90

2.25 = 0.87 * B

=> B = 2.25/0.87

B = 2.59 T

The magnetic field strength between the poles is 2.59 T

4 0
2 years ago
Help with these please someone?
DIA [1.3K]

Answer:

8. 2.75·10^-4 s^-1

9. No, too much of the carbon-14 would have decayed for radiation to be detected.

Explanation:

8. The half-life of 42 minutes is 2520 seconds, so you have ...

1/2 = e^(-λt) = e^(-(2520 s)λ)

ln(1/2) = -(2520 s)λ

-ln(1/2)/(2520 s) = λ ≈ 2.75×10^-4 s^-1

___

9. Reference material on carbon-14 dating suggests the method is not useful for time periods greater than about 50,000 years. The half-life of C-14 is about 5730 years, so at 65 million years, about ...

6.5·10^7/5.73·10^3 ≈ 11344

half-lives will have passed. Whatever carbon 14 may have existed at the time will have decayed completely to nothing after that many half-lives.

7 0
3 years ago
In what ways is n2 gas removed from the atmosphere?
MaRussiya [10]
One way of removing nitrogen gas from the atmosphere is by natural nitrogen fixation. This is done by nitrogen-fixing bacteria in the oceans and in the soil. Nitrogen fixation is a process that converts the nitrogen in air to ammonia.
3 0
3 years ago
What causes a star to shine brightly
steposvetlana [31]

what causes a star to shine brightly:

by squeezing atoms together in its core

5 0
3 years ago
Read 2 more answers
Given that: = 2i + 9j +3k and = -i – 4k . Find
Igoryamba

Answer:

3i+9j= -7k

Explanation:

2i+I+9j=-4k-3k

3i+9j= -7k

7 0
2 years ago
Other questions:
  • Sam has been working to improve his muscular fitness. He jumps rope and trains with weights. What will most likely be the result
    12·2 answers
  • 3. what could you do to increase the precision of your measurements? What factors limit the
    8·1 answer
  • What is the effect in the picture
    8·1 answer
  • Most granite has a (blank) of quartz,mica,and feldspar
    8·1 answer
  • Which statements about the moon’s phases are true? Check all that apply.
    12·2 answers
  • You wiggle a string, that is fixed to a wall at the other end, creating a sinusoidal wave with a frequency of 2.00 Hz and an amp
    11·1 answer
  • Gold has a density of 19300 kg/m3 calculate the mass of 0.02m3 of gold in kilograms​
    12·1 answer
  • A 1250-kg car moves at 20.0 m/s. How much work must be done on the car to increase its speed to 30.0 m/s.
    11·1 answer
  • Two male rabbits live in a habitat together. They both compete for mates and territory during the spring months. This is an exam
    14·2 answers
  • Why did astronomers suspect an eighth planet beyond uranus? how did they determine where to look for it? construct the correct e
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!