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sukhopar [10]
3 years ago
14

A test charge is placed at a distance of 3.5 meters from a charge of 8.7 × 10-9 coulombs. What is the electric field strength at

the test charge? (k = 9.0 × 109 newton·meter2/coulomb2) 6.4 newtons/coulomb 8.7 newtons/coulomb 3.5 newtons/coulomb 9.0 newtons/coulomb Done
Physics
1 answer:
zavuch27 [327]3 years ago
8 0
In order to calculate the electric field strength, we may use the formula:
E = kQ/d²
Where Q is the charge and d is the distance between the charge and the test charge. Substituting the values into the equation:
E = (9 x 10⁹)(8.7 x 10⁻⁹) / (3.5²)
E = 6.39 Newtons per coulomb

Therefore, the answer is 6.4 Newtons/coulomb
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If the equation of an average velocity of a sport car was given by the equation V(t) = 3t^2 -6t +24. Determine its displacement
alisha [4.7K]

Answer:

72

Explanation:

The displacement of an object can be found from the velocity of the object by integrating the expression for the velocity.

In this problem, the velocity of the sport car is given by the expression

v(t)=3t^2-6t+24

In order to find the expression for the position of the car, we integrate this expression. We find:

x(t)=\int v(t) dt=t^3-3t^2+24t+C

where C is an arbitrary constant.

Here we want to find the displacement after 3 seconds. The position at t = 0 is

x(0)=0^3-0+0+C=C

While the position after t = 3 s is

x(3)=3^3-3(3)^2+24(3)+C=72+C

Therefore, the displacement of the car in 3 seconds is

d=x(3)-x(0)=72+C-C=72

7 0
3 years ago
Which of the following are Electromagnetic Waves?
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b

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Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 7.1 g. Silver has 47 electrons
Assoli18 [71]

<u>Answer:</u> The number of electrons in given amount of silver are 1.87\times 10^{24}

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We are given:

Given mass of silver = 7.1 g

Molar mass of silver = 107.87 g/mol

Putting values in above equation, we get:

\text{Moles of silver}=\frac{7.1g}{107.87g/mol}=0.066mol

Number of electrons in 1 atom of silver = 47

According to mole concept:

1 mole of an element contains 6.022\times 10^{23} number of particles

So, 0.066 moles of silver will contain = -(0.066\times 47\times 6.022\times 10^{23})=1.87\times 10^{24} number of electrons

Hence, the number of electrons in given amount of silver are 1.87\times 10^{24}

7 0
3 years ago
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