A test charge is placed at a distance of 3.5 meters from a charge of 8.7 × 10-9 coulombs. What is the electric field strength at

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A test charge is placed at a distance of 3.5 meters from a charge of 8.7 × 10-9 coulombs. What is the electric field strength at

the test charge? (k = 9.0 × 109 newton·meter2/coulomb2) 6.4 newtons/coulomb 8.7 newtons/coulomb 3.5 newtons/coulomb 9.0 newtons/coulomb Done

Physics

1 answer:

zavuch27 [327] · Answer 1 · 2022-08-04T09:03:21+03:00

In order to calculate the electric field strength, we may use the formula:
E = kQ/d²
Where Q is the charge and d is the distance between the charge and the test charge. Substituting the values into the equation:
E = (9 x 10⁹)(8.7 x 10⁻⁹) / (3.5²)
E = 6.39 Newtons per coulomb

Therefore, the answer is 6.4 Newtons/coulomb