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sukhopar [10]
3 years ago
14

A test charge is placed at a distance of 3.5 meters from a charge of 8.7 × 10-9 coulombs. What is the electric field strength at

the test charge? (k = 9.0 × 109 newton·meter2/coulomb2) 6.4 newtons/coulomb 8.7 newtons/coulomb 3.5 newtons/coulomb 9.0 newtons/coulomb Done
Physics
1 answer:
zavuch27 [327]3 years ago
8 0
In order to calculate the electric field strength, we may use the formula:
E = kQ/d²
Where Q is the charge and d is the distance between the charge and the test charge. Substituting the values into the equation:
E = (9 x 10⁹)(8.7 x 10⁻⁹) / (3.5²)
E = 6.39 Newtons per coulomb

Therefore, the answer is 6.4 Newtons/coulomb
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