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3 years ago

12

A ______ psychologist held children with learning problems and works with teacher and parents to create a healthy environment.

1 answer:

Savatey [412]3 years ago

6 0

C, I think? maybe .............

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ANSWER As Soon As Possible

klemol [59]

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Explanation:

8 0

3 years ago

Read 2 more answers

An electron and a proton, starting from rest, are accelerated through an electric potential difference of the same magnitude. in

Yakvenalex [24]

The charges are the same in absolute value, so the change of potential energy is the same. That means that the change in kinetic energy is also the same. Then:

1 = Ke/Kp = m_e *v_e^2 / m_p * v_p^2, or

v_e/v_p = sqrt( m_p/m_e),

So the speed of the electron will be sqrt( m_p/m_e) times greater than the speed of the proton

4 0

3 years ago

A mass on a spring oscillates with a period T. Part A If both the mass and the force constant of the spring are doubled, the new

garik1379 [7]

Answer:

The new time period will be T.

Explanation:

The time period in terms of spring constant and mass is given by :

$T=2\pi\sqrt{\dfrac{m}{k}}$

If mass and force constant is doubled, m' = 2m and k' = 2k

New time period is given by :

$T'=2\pi\sqrt{\dfrac{m'}{k'}}$

$T'=2\pi\sqrt{\dfrac{2m}{2k}}$

$T'=2\pi\sqrt{\dfrac{m}{k}}$

$T'=T$

So, the new period will remains the same. Hence, the correct option is (C).

4 0

3 years ago

A conducting sphere of radius R1 carries a charge Q. Another conducting sphere has a radius R2 = 3 4 R1, but carries the same ch

Blizzard [7]

Answer:

The ratio of electric field is 16:9.

Explanation:

Given that,

Radius $R_{2}=\dfrac{3}{4}R_{1}$

Charge = Q

We know that,

The electric field is directly proportional to the charge and inversely proportional to the square of the distance.

In mathematically term,

$E=\dfrac{kQ}{R^2}$

Here, $E\propto\dfrac{1}{R^2}$

We need to calculate the ratio of electric field

Using formula of electric field

$\dfrac{E_{2}}{E_{1}}=\dfrac{R_{1}^2}{R_{2}^2}$

Put the value into the formula

$\dfrac{E_{2}}{E_{1}}=\dfrac{(4R_{1})^2}{(3R_{1})^2}$

$\dfrac{E_{2}}{E_{1}}=\dfrac{16}{9}$

Hence, The ratio of electric field is 16:9.

5 0

4 years ago

What are some common measurements that are given as a rate?

BabaBlast [244]

Answer:

taco bell

Explanation:

6 0

4 years ago