Answer:
If a vertical line extending down from an object's CG extends outside its area of support, the object will topple
Explanation:
We can understand better this situation using a diagram with the forces acting on it.
In the attached image we can see that when the gravity center is bouncing outside from the area of the pedestal, the object will be out of balance and will fall.
We can't see black holes because D) no light can get out
Explanation:
Black holes are the result of the gravitational collapse of a supermassive star.
The life of a supermassive star ends with a huge explosion, called supernova, that leaves behing a super-dense core called black hole.
Black holes are the most dense objects of the universe, having a huge mass in a super small size. For this reason, the gravitational force exerted by a black hole in its proximity is so strong that even light is not able to escape from the gravitational field. For this reason, light from a black hole is not able to reach us, and so we are not able to see these objects.
The "edge" of space beyond which light remains "trapped" inside the black hole is called event horizon, and no object can escape this region of space.
The radius of the event horizon of a black hole is called Schwarzschild radius and it is given by:
where
G is the gravitational constant
M is the mass of the black hole
c is the speed of light
Learn more about space:
#LearnwithBrainly
Answer:
7g/cm³
Explanation:
The formula for density is . Let's apply the formula to the question:
= 7
g/cm³
Answer:
W = 2.3 10²
Explanation:
The force of the weight is
W = m g
let's use the concept of density
ρ= m / v
the volume of a sphere is
V = π r³
V = π (1.0 10⁻³)³
V = 4.1887 10⁻⁹ m³
the density of water ρ = 1000 kg / m³
m = ρ V
m = 1000 4.1887 10⁻⁹
m = 4.1887 10⁻⁶ kg
therefore the out of gravity is
W = 4.1887 10⁻⁶ 9.8
W = 41.05 10⁻⁶ N
now let's look for the electric force
F_e = q E
F_e = 12 10⁻¹² 15000
F_e = 1.8 10⁻⁷ N
the relationship between these two quantities is
= 41.05 10⁻⁶ / 1.8 10⁻⁷
\frac{W}{F_e} = 2,281 10²
W = 2.3 10²
therefore the weight of the drop is much greater than the electric force