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insens350 [35]
3 years ago
15

A sample of matter was given the following description: The sample of the pure substance is blue in color with an octahedral sha

pe with very distinct edges. Into which of the classification would this sample belong?
Chemistry
1 answer:
Alexeev081 [22]3 years ago
5 0

Answer:

A crystalline solid

Explanation:

Most solids form with a regular arrangement of their particles because the overall attractive interactions between particles are maximized, and the total intermolecular energy is minimized, when the particles pack in the most efficient manner. The regular arrangement at an atomic level is often reflected at a macroscopic level.  Liquids dont use to have this kind of arrangements or shapes.

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A solution is prepared by pipetting 20.00 mL of a 1.00 x 10-3 M NaCl solution into a 250.0 mL volumetric flask. The flask is dil
oee [108]

Answer:

The concentration of the newly prepared solution is 8 * 10^-5 M

Explanation:

The most common way to solve this problem is to use the following formula

c1*V1 = c2*V2

with c1 = 1 * 10^-3 M

with V1 = 20 mL = 0.02 L

with c2 = TO BE DETERMINED

with V2 = 250 mL = O.250 L

10^-3 * 0.02 L = c2 * 0.250L

0.00002 = c2 * 0.250L

c2 = 0.00002 / 0.250 L

c2 = 0.00008 M = 8 * 10^-5 M

The concentration of the newly prepared solution is 8 * 10^-5 M

3 0
3 years ago
What is the name of the compound shown here
Naya [18.7K]

ethane is the compound of the answer you are asking help

3 0
3 years ago
Calculate the entropy change for the reaction: Fe2O3(s) +3C(s) -> 2Fe(s) + 3CO(g)
Gelneren [198K]

Answer:

ΔS = +541.3Jmol⁻¹K⁻¹

Explanation:

Given parameters:

Standard Entropy of Fe₂O₃ = 90Jmol⁻¹K⁻¹

Standard Entropy of C = 5.7Jmol⁻¹K⁻¹

Standard Entropy of Fe = 27.2Jmol⁻¹K⁻¹

Standard Entropy of CO = 198Jmol⁻¹K⁻¹

To find the entropy change of the reaction, we first write a balanced reaction equation:

                              Fe₂O₃ +  3C →  2Fe + 3CO

To calculate the entropy change of the reaction we simply use the equation below:

      ΔS = ∑S_{products} - ∑S_{reactants}

Therefore:

     ΔS = [(2x27.2) + (3x198)] - [(90) + (3x5.7)] = 648.4 - 107.1

                          ΔS = +541.3Jmol⁻¹K⁻¹

5 0
3 years ago
Fluorine-18 is produced by reacting oxygen-18 with a proton, 11p. The products of this reaction are fluorine-18, a neutron, and
Tanya [424]

₈O¹⁸ + ₁¹H(proton) ⇒ ₉F¹⁸ + ₀n¹(neutron) + ₀γ⁰ (gamma)

<h3>Further explanation</h3>

Given

Fluorine-18

Oxygen-18

Required

Nuclear equation

Solution

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

  • alpha α particles ₂He⁴
  • beta β ₋₁e⁰ particles
  • gamma particles ₀γ⁰
  • positron particles ₁e⁰
  • neutron ₀n¹

The principle used is the sum of the atomic number and mass number before and after the decay reaction is the same

The reaction

₈O¹⁸ + ₁¹H(proton) ⇒ ₉F¹⁸ + ₀n¹(neutron) + ₀γ⁰ (gamma)

7 0
3 years ago
a compound is found to contain 31.1% sulfur and 68.9% chlorine determine the empirical formula for the sulfur and chlorine sampl
ollegr [7]

Answer:

Empirical formula = S₁Cl₂ = SCl₂

Explanation:

The empirical formula of a compound is the simplest whole number ratio of each type of atom in a compound.

This compound contains 31.1% sulfur and 68.9% chlorine.

That is 100g of the compound contains 31.1 g of sulfur and 68.9 g of chlorine.

Convert the mass of each element to moles using the molar mass from the periodic table.

Moles of Sulfur = \frac{31.1}{32.065 } \\

= 0.9699

Moles of Chlorine= \frac{68.9}{35.453 } \\

= 1.9434

Divide each mole value by the smallest number of moles calculated.

Units of sulfur =  \frac{0.9699}{0.9699} \\

= 1

Units of Chlorine =  \frac{1.9434}{0.9699} \\

= 2

Empirical formula = S₁Cl₂ = SCl₂

8 0
3 years ago
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