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insens350 [35]
3 years ago
15

A sample of matter was given the following description: The sample of the pure substance is blue in color with an octahedral sha

pe with very distinct edges. Into which of the classification would this sample belong?
Chemistry
1 answer:
Alexeev081 [22]3 years ago
5 0

Answer:

A crystalline solid

Explanation:

Most solids form with a regular arrangement of their particles because the overall attractive interactions between particles are maximized, and the total intermolecular energy is minimized, when the particles pack in the most efficient manner. The regular arrangement at an atomic level is often reflected at a macroscopic level.  Liquids dont use to have this kind of arrangements or shapes.

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madreJ [45]
Jasmine have 20 fish because4 times 5 equals 20
4 0
3 years ago
what biome has many nocturnal animals that burrow underground during the day that are active at night
hram777 [196]

Answer:

it could be maybe a raccoon or a possum

Explanation:

4 0
3 years ago
An ideal gas is brought through an isothermal compression process. The 3.00 mol of gas goes from an initial volume of 261.6×10−6
Eduardwww [97]

Answer : The temperature and the final pressure of the gas is, 586.83 K and 1.046\times 10^{9}atm respectively.

Explanation : Given,

Initial volume of gas = 261.6\times 10^{-6}m^3

Final volume of the gas = 138.2\times 10^{-6}m^3

Heat released = -9340 J

First we have to calculate the temperature of the gas.

According to the question, this is the case of isothermal reversible compression of gas.

As per first law of thermodynamic,

\Delta U=q+w

where,

\Delta U = internal energy

q = heat

w = work done

As we know that, the term internal energy is the depend on the temperature and the process is isothermal that means at constant temperature.

So, at constant temperature the internal energy is equal to zero.

q=-w

Thus, w = -q = 9340 J

The expression used for work done will be,

w=nRT\ln (\frac{V_2}{V_1})

where,

w = work done = 9340 J

n = number of moles of gas  = 3 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas  = ?

V_1 = initial volume of gas

V_2 = final volume of gas

Now put all the given values in the above formula, we get the temperature of the gas.

9340J=3mole\times 8.314J/moleK\times T\times \ln (\frac{261.6\times 10^{-6}m^3}{138.2\times 10^{-6}m^3})

T=586.83K

Now we have to calculate the final pressure of the gas by using ideal gas equation.

PV=nRT

where,

P = final pressure of gas = ?

V = final volume of gas = 138.2\times 10^{-6}m^3=138.2\times 10^{-9}L

T = temperature of gas = 586.83 K

n = number of moles of gas = 3 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get:

P\times (138.2\times 10^{-9}L)=3mole\times (0.0821L.atm/mole.K)\times (586.83K)

P=1.046\times 10^{9}atm

Therefore, the temperature and the final pressure of the gas is, 586.83 K and 1.046\times 10^{9}atm respectively.

6 0
3 years ago
Answer pls:) <br><br> What is the mass of 8.944 x 1018 iron atoms in cg?
DENIUS [597]
It’s the 8x7x9 for me
6 0
3 years ago
In the laboratory you dilute 2.49 ml of a concentrated 6.00 m hydrochloric acid solution to a total volume of 50.0 ml. what is t
Marizza181 [45]
Equation: M1V1 = M2V2

Where M = concentration & V = volume

Step 1: Write down what is given and what you are trying to find

Given: M1 = 6.00M, V1 = 2.49mL, and V2 = 50.0mL
Find: M2

Step 2: Plug in the values into the equation

M1V1 = M2V2
(6.00M)(2.49mL) = (M2)(50.0mL)

Step 3: Isolate the variable (Divide both sides by 50.0mL so M2 is by itself)

(6.00M)(2.49mL) / (50.0mL) = M2

Answer: M2 = 0.30M 
*Don't forget sig figs & units!
4 0
3 years ago
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