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GarryVolchara [31]
3 years ago
6

Question 8 of 10

Chemistry
1 answer:
Harlamova29_29 [7]3 years ago
7 0

Answer:

D

Explanation:

Because it is answered with a letter

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4 0
3 years ago
Need to complete the chart
GalinKa [24]

Answer:

Row 1

[H^+]=1.8\times 10^{-6}M

pH=-\log[H^+]=-\log[1.8\times 10^{-6}]=5.7

pOh=14-pH=14-5.7=8.3

pOH=-\log[OH^-]

[OH^-]=0.5\times 10^{-8}M

Hence, acidic

Row 2

[OH^-]=3.6\times 10^{-10}M

pOH=-\log[OH^-]=-\log[3.6\times 10^{-10}]=9.4

pH=14-pOH=14 - 9.4 = 4.6

pH=-\log[H^+]

[H^+]=2.6\times 10^{-5}M

Hence, acidic

Row 3

pH = 8.15

[H^+]=0.7\times 10^{-8}M

pOH=14-pH=14 - 8.15 = 5.8

pOH=-\log[OH^-]

[OH^-]=1.5\times 10^{-6}M

Hence, basic

Row 4

pOH = 5.70

[OH^-]=1.8\times 10^{-6}M

pH=14-pOH=14 - 5.70 = 8.3

pH=-\log[H^+]

[H^+]=0.5\times 10^{-8}M

Hence, basic



3 0
3 years ago
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